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andrezito [222]
3 years ago
9

Javier and tommy have money in their wallets. The sum of their money is $43. Javier has $11 more than Tommy. How much money do t

hey both have ?
Mathematics
1 answer:
Savatey [412]3 years ago
4 0

Answer:

Javier has 27, Tommy has 16

Step-by-step explanation:

43-11=32

32/2=16

16+11=27

Check: 27+16=43

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9. Ms. Barton determined that the
finlep [7]

Answer:

B. 95

Step-by-step explanation:

Plug in 8625 into the equation as c:

c = 75n + 1500

8625 = 75n + 1500

Solve for n:

7125 = 75n

95 = n

So, 95 people attended.

6 0
3 years ago
Read 2 more answers
a population has a mean of 25 median of 24 and mode of 26 the standard deviation is 5 the value for the
Arada [10]

Complete Question

A population has a mean of 25, a median of 24, and a mode of 26. The standard deviation is 5. The value of the 16th percentile is _______. The range for the middle 3 standard deviation is _______.

Answer:

The  value  of the 16th percentile  is  x = 20

The range for the middle 3 standard deviation is  10 \to 40

Step-by-step explanation:

From the question we are told that

     The  mean is  \mu  =  25

     The  median is  m  =  24

     The  mode is  n =  26

     The  standard deviation is  \sigma  =  5

Generally the 16th percentile is mathematically represented as

  P(x)= P(\frac{X  -  \mu }{ \sigma }   \le \frac{x- 25 }{5} ) = 0.16[/teGenerally  [tex]\frac{X -  \mu}{\sigma }  =  Z(The  \  standardized \  value \ of  \ X  )

So

       P(x) =  P(Z \le \frac{ x -  25}{5} ) =  0.16

Now from the normal distribution table  the z-score of  0.16 is  

      z =  -1

       P(x) =  P(Z \le \frac{ x -  25}{5} ) =  P(Z \le -1 )

=>  \frac{x- 25}{5}  =  -1

=>    x- 25  =  -5

=>      x =  25-5

=>       x = 20

The range for the middle 3 standard deviation is mathematically represented

        \mu  -  3\sigma \to \mu + 3\sigma

        25 -  3(5 ) \to 25 +  3(5 )

         10 \to 40

 

   

3 0
2 years ago
two mountain bikers leave from the same parking lot and head in opposite directions on two different trails. the first rider goe
sveta [45]

Applying the required <em>rule </em>or <em>theorem</em>, it can be concluded that the second biker is <u>farther</u> from the <em>parking lot</em>. The distance of the bikers to the <em>parking lot</em> are:

i. First biker = 17.0 km

ii. Second biker = 20.22 km

The <u>path</u> of travel of both bikers would form a triangle. Applying the <u>Pythagoras</u> theorem to the path of the <em>first</em> biker would give his <u>distance</u> from the starting point. While applying the <u>cosine</u> rule to the path of <em>second</em> rider would gives his <u>distance</u> to the starting point.

Thus,

a. <u>To determine the distance of the first biker from the parking lot.</u>

Let the required <em>distance </em>be represented by x. Applying the Pythagoras theorem, we have:

hyp^{2} = adj 1^{2} + adj 2^{2}

x^{2} = 8^{2} + 15^{2}

   = 64 + 225

   = 289

x = \sqrt{289}

  = 17

x = 17 km

Thus, the <u>first</u> biker is 17.0 km from the <em>starting</em> point.

b. <u>To determine the distance of the second biker from the parking lot.</u>

Let the required <em>distance</em> be represented by x. So that applying the cosine rule, we have:

c^{2} = a^{2} + b^{2} - 2ab Cos θ

x^{2} = 8^{2} + 15^{2} - 2(15*8) Cos (180 - 20)

    = 64 + 225 - 240 Cos 160

    = 289 - 240 * -0.5

x^{2} = 289 + 120

   = 409

x = \sqrt{409}

 = 20.2237

x = 20.22 km

Thus, the <u>second</u> biker is 20.22 km from the <em>starting</em> point.

Therefore, the second biker is <u>farther</u> from the <em>parking lot</em>.

A sketch of the path of travel for the two bikers is attached for more clarifications.

Visit: brainly.com/question/22699651

7 0
1 year ago
What direction will this parabola open?
butalik [34]

Answer:

Step-by-step explanation:

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2 years ago
Why do you need fewer inches than centimeters to measure the length of the key
kirill [66]
Inches and centimeters are different units of measurement, one English, one metric.  Converting from one to the other requires use of a conversion factor.
One such factor can be derived from    1 inch = 2.54 cm.  This means that one inch is 2.54 times longer than one cm.
6 0
3 years ago
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