So here is the answer. Initially, Ed's toy cars compared to Pete's toy cars was 5:2. So for every 5 cars that Ed has, Pete has 2. Now that Ed gave 30 cars to Pete. So here it goes. The total number of ratio units is 5+2=7, so each will have an equal number if they both have 3.5 ratio units. That is, if Ed transfers to Pete 1.5 ratio units, their car counts will be equal. Thus 1.5 ratio units = 30 cars, or 1 ratio unit = 20 cars. Therefore, this makes <span> 7*20 cars = 140 cars.
</span>Hope this helps.
Answer: 5:8
Step-by-step explanation:
By reducing both sides equally, the ending answer is 5:8
(There can be many answers to your question but the one i told you is the most reduced one)
Answer:
y = x^2/ 60 + 15
=>( x - h)^2 = 4a[ (x^2/6 + 15) - k ].
Step-by-step explanation:
Okay, in order to solve this question very well, one thing we must keep at the back of our mind is that the representation for the equation of a parabola is given as ; y = ax^2 + bx + c.
That is to say; y = ax^2 + bx + c is the equation for a parabola. So, we should be expecting our answer to be in this form.
So, from the question above we are given that "the satellite dish will be in the shape of a parabola and will be positioned above the ground such that its focus is 30 ft above the ground"
We will make an assumption that the point on the ground is (0,0) and the focus is (0,30). Thus, the vertex (h,k) = (0,15).
The equation that best describes the equation of the satellite is given as;
(x - h)^2 = 4a( y - k). ------------------------(1).
[Note that if (h,k) = (0,15), then, a = 15].
Hence, (x - 0)^2 = (4 × 15) (y - 15).
x^2 = 60(y - 15).
x^2 = 60y - 900.
60y = x^2 + 900.
y = x^2/ 60 + 15.
Hence, we will have;
(x - h)^2 = 4a[ (x^2/6 + 15) - k ].
Answer:
(
3
x
2
+
3
x
+
4
)
(
2
x
−
1
)
Step-by-step explanation:
Answer:
There is an infinite number of solutions.
Step-by-step explanation:
When you simplify the left side of the equation, you get -7n - 14, which is equal to the right side. If you were to plug in any number for n, it will equal the same on both sides of the equation.
