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Gwar [14]
3 years ago
13

Marlene rides her bike at a rate of 16 miles per hour. The time in hours that she rides is represented by the variable t, and th

e distance she rides is represented by the variable d. Which statements are true of the scenario? Check all that apply.
*The independent variable, the input, is the variable d, representing distance.
*The distance traveled depends on the amount of time Marlene rides her bike.
*The initial value of the scenario is 16 miles per hour.
*The equation t = d + 16 represents the scenario.
*The function f(t) = 16t represents the scenario.

Mathematics
2 answers:
White raven [17]3 years ago
8 0

Let

t--------> the time in hours

d-------> the distance in miles

we know that

d=16t

this is a linear equation that represent the scenario

in this equation the independent variable is the time t and the dependent variable is the distance d

The distance's equation in function notation is equal to

f(t)=16t

Using a graph tool

see the attached figure

The domain of the function is the interval----------> [0,∞)

t\geq0

The range of the function is the interval------->  [0,∞)

f(t)\geq0

<u>Statements</u>

<u>a) The independent variable, the input, is the variable d, representing distance</u>

The statement is false

Because the  independent variable is the variable t

<u>b) The distance traveled depends on the amount of time Marlene rides her bike</u>

The statement is true

Because the distance's equation in function notation is equal to

f(t)=16t

<u>c) The initial value of the scenario is 16 miles per hour</u>

The statement is false

Because 16 represent the rate or  the slope of the linear equation

<u>d) The equation t = d + 16 represents the scenario</u>

The statement is false

Because, the scenario is represented by the function f(t)=16t

<u>e) The function f(t) = 16t represents the scenario</u>

The statement is true

kotegsom [21]3 years ago
7 0

Answer:

the correct answer is

b and e

just took the test.

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Answer:

CLASS     FREQUENCIES     RELATIVE FREQUENCIES

A                        60                                 0.5

B                        12                                  0.1

C                        48                                 0.4

TOTAL              120                                  1

Step-by-step explanation:

Given that;

the frequencies of there alternatives are;

Frequency A = 60

Frequency B = 12

Frequency C = 48

Total = 60 + 12 + 48 = 120

Now to determine our relative frequency, we divide each frequency by the total sum of the given frequencies;

Relative Frequency A = Frequency A / total = 60 / 120 = 0.5

Relative Frequency B = Frequency B / total = 12 / 120 = 0.1

Relative Frequency C = Frequency C / total = 48 / 120 = 0.4

therefore;

CLASS     FREQUENCIES     RELATIVE FREQUENCIES

A                        60                                 0.5

B                        12                                  0.1

C                        48                                 0.4

TOTAL              120                                  1

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