Answer:
Step-by-step explanation:
when, for each x in the domain of f, f(x) 6. A function f Skills and Applications 回避回Domain, Range, and Values of a is , 13. Function In Exercises 7-10, use the graph of the function to find the domain and range of f and each function value. 7. (a) f(-1) (b) f(0) 8. (a) f(-1) (b) f(0 15. f(x) 16. f(x) 17. f(x) 18. f(x) 19. f(x 4-2 2 4 6 (c) f(3) (d) f(-1)(c) f(0 (d) f(2) y | y =f(x) 20. f(x 4 2 21. f(x 22. f(x 23. f(a 24. f( 2 回 回Vertical Line Test for Functions In 25. f Exercises 11-14, use the Vertical Line Test to determine whether the graph represents y as a function of x. To print an enlarged copy of Graph the graph, go to MathGraphs.com. 窝 (a) use
Let x be one number and y be the other.
#1 - Set up a system of equations.
4x = y
x + y = 45
#2 - Solve the system by substitution.
x + (4x) = 45
5x = 45
x = 9
(9) + y = 45
y = 36
Step-by-step explanation:
Hope this is correct
Have a good day!
Answer:
a) Not a function
b) It is a function
c) It is a function
Step-by-step explanation:
a) f(S) is not completly well defined, becuase if the bistring has multiple zeros, you need to pick one and there is not specified method in how you would do so. Another reason for which f is not well defined as a function is that for a bistring with only 1's, f is not defined because there is no zero.
b) This is a function. f(S) returns a concrete and unique integer number for each bistring S. If the bistring has only zeros, the f(S) = 0.
c) This is well defined as a function. It compensates for the failures of the first definition:
- If multiple zeros appears in S, you pick the first one, so there is one possible value for f(S)
-If no zeros appear, f is still well defined because it takes the value 0, as specified in the definition.
The answer is 12. if you need help, do 60•.2
