Answer:
(-3y5)3
-9y15
Step-by-step explanation:
prove me wrong
D. 3
For g(x) = |x|, we seem to have ...
f(x) = 3|x| = 3g(x) = a·g(x)
The value of 'a' is 3.
The solution is in the attachment
mean= sum of the terms/ (over) number of terms
Answer: 84 is your answer hope this helped
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