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charle [14.2K]
3 years ago
9

URGENT PLEASE HELP Select the correct solution set. x + 17 ≤ -3 {x | x ≤ -20} {x | x ≤ 14} {x | x ≥ -20}

Mathematics
1 answer:
grigory [225]3 years ago
7 0

Answer:

The correct answer is the first solution set.

Step-by-step explanation:

If we substitute -20 into the equation we get

-20+17≤-3

-3≤-3

So,the inequality is right.

We can check the second one

14+17≤-3

31≤3 The inequality is false.

We can check the last one

-20+17≤-3

-3≤3 It works however there is a difference between the first one and the last one and that is the sign.For the first one there x≤-20 meaning the greatest number x can be is -20.For the last one x≥-20 which means -20 is the least value x can be.

If we substitude -21 into the equation we get

-21+17≤-3

-4≤-3

The inequality is false because -4 is not smaller than -3.

So,the right answer is the first solution set.

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<span>The first term of a geometric sequence is 4 and the multiplier, or ratio, is 2. what is the sum of the first 5 terms of the sequence?
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a_1=4\\&#10;a_2=2*a_1=8\\&#10;a_3=2*a_2=2^2*a_1=4*4=16\\&#10;a_4=2^3*a_1=8*4=32\\&#10;a_5=2^4*a_1=16*4=64\\&#10;&#10;4+8+16+32+64=124&#10;&#10;

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Answer:

The ball travel horizontally 37 feet before it hits the ground

Step-by-step explanation:

we have

A(x)=-0.02x^2+0.6x+5

where

x ----> is the horizontal distance in feet

A --->  is the altitude of the ball, in feet.

we know that

When the ball hit the ground, the altitude of the ball is equal to zero

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The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

-0.02x^2+0.6x+5=0

so

a=-0.02\\b=0.6\\c=5

substitute in the formula

x=\frac{-0.6\pm\sqrt{0.6^{2}-4(-0.02)(5)}} {2(-0.02)}

x=\frac{-0.6\pm\sqrt{0.76}} {-0.04}

x=\frac{-0.6\pm0.87} {-0.04}

x=\frac{-0.6+0.87} {-0.04}=-6.75

x=\frac{-0.6-0.87} {-0.04}=36.75

therefore

The ball travel horizontally 37 feet before it hits the ground

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