Consider this option:
1. if the point (4;6) is the centre of the circle and the point (2;5) is the first endpoint of its diameter, then point (4;6) is the middle point of the diameter (it means that is the middle between the 1st and the 2d endpoints of diameter).
2. using the property described above:
for x of the 2d endpoint of the diameter: x=4*2-2=6;
for y of the 2d endpoint of the diameter: y=6*2-5=7.
answer: (6;7)
Center c and a scale factor of 2
Answer:
It is the distance that - 5 is from 0 on the number line.
Step-by-step explanation:
We have to select a statement that is true about the value of StartAbsoluteValue negative 5 EndAbsoluteValue i.e. |- 5|
Definition of the absolute value function is given by, |x| = x for, x ≥ 0 and |x| = - x for x < 0.
Now, an absolute value function gives the positive value of any value in the function i.e. |- 5| = 5.
Therefore, it is the distance that - 5 is from 0 on the number line. (Answer)
1/6^3 is also equivalent to 6^-3. It can be reverted back to 1/216. Answers on ed2020 are A. and D.
16 can be expressed as a difference of two prime numbers in two ways, which
is:23 - 7 = 16, 19 - 3 = 16
Among the choices, 16 is expressed as (23 - 7), which is the difference of two prime numbers.
