What is the answer ?

Multiple choice easy question. Please answer.

Anton [14]

Answer:

I belive it should be # 3 i might be wrong thow.

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Dora buys one package each of 1- pound, 2- pound, and 4-pound packages if ground beef to make hamburgers. How many 1/4-pound ham

Alisiya [41]

82. Dora bought one package of each 1-pound pork, 2-pound pork and 4-pound pork. Thus, she got a total of: => 1 pound + 2 pounds + 4 pounds = 7 pounds of pork. Question: How many ¼ pound of hamburger she can make then with this given number of pork in pounds. => ¼ = 1 / 4 = .25 Now, let’s divide 7 pounds by .25 pounds => 7 / .25 = 28 Thus, She can make 28 hamburgers in all.

7 0

3 years ago

If a random sample of size nequals=6 is taken from a population, what is required in order to say that the sampling distributio

goldenfox [79]

Answer:

$\bar X \sim N(\mu , \frac{\sigma}{\sqrt{n}})$

In order to satisfy this distribution we need that each observation on this case comes from a normal distribution, because since the sample size is not large enough we can't apply the central limit theorem.

Step-by-step explanation:

For this case we have that the sample size is n =6

The sample man is defined as :

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

And we want a normal distribution for the sample mean

$\bar X \sim N(\mu , \frac{\sigma}{\sqrt{n}})$

In order to satisfy this distribution we need that each observation on this case comes from a normal distribution, because since the sample size is not large enough we can't apply the central limit theorem.

So for this case we need to satisfy the following condition:

$X_i \sim N(\mu , \sigma), i=1,2,...,n$

Because if we find the parameters we got:

$E(\bar X) =\frac{1}{n} \sum_{i=1}^n E(X_i) = \frac{n\mu}{n}=\mu$

$Var(\bar X)= \frac{1}{n^2} \sum_{i=1}^n Var(X_i) = \frac{n\sigma^2}{n^2}= \frac{\sigma^2}{n}$

And the deviation would be:

$Sd (\bar X) = \frac{\sigma}{\sqrt{n}}$

And we satisfy the condition:

$\bar X \sim N(\mu , \frac{\sigma}{\sqrt{n}})$

3 0

2 years ago

Ginger is pregnant with a fifth child, a son. What is the probability that this son will be affected by Lalaphobia?

Rom4ik [11]

Answer:

We need more information to answer this question but if the other 4 children that were already born, if 2 or 3 out of the 4 were effected by Lalaphobia, then the 5th is 50% to 75% likely to be affected as well

6 0

3 years ago

16. Evaluate 3•7 - 1. O -5 O 21 20 18

Greeley [361]

Step-by-step explanation:

3.7-1

point in mathematics mean multiplication

so

3*7-1

21-1

20

7 0

2 years ago

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What is the answer ?