The standard form of the quadratic function f(x) = -3x^2 + 6x - 2 is f(x) = -3x^2 + 6x - 2
<h3>How to represent the
quadratic function in standard form?</h3>
The quadratic function is given as
f(x) = -3x^2 + 6x - 2
The standard form of a quadratic function is represented as:
f(x) = ax^2 + bx + c
When both equations are compared, we can see that the function f(x) = -3x^2 + 6x - 2 is already in standard form
Where
a = -3
b = 6
c = -2
Hence, the standard form of the quadratic function f(x) = -3x^2 + 6x - 2 is f(x) = -3x^2 + 6x - 2
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Answer:
Step-by-step explanation:
<u>Use properties of rhombus:</u>
- diagonals are perpendicular
- diagonals are angle bisectors
- opposite angles are equal
<u>The angle measures are:</u>
- m∠2 = 90°
- m∠3 = 70°
- m∠1 = m∠4 = 90° - 70° = 20°
Da answer is 21,000 Pounds Couse 9 + 10 = 21
Answer:
455666
124
Step-by-step explanation:
Answer:
Step-by-step explanation:
Quotient is the number remained after divident is divided by divisor