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mote1985 [20]
3 years ago
14

xia has 16 meters of rope. She cuts off 1/6 of the rope to use as a skipping rope for a party activity. how long is xias skippin

g rope
Mathematics
2 answers:
Alenkinab [10]3 years ago
8 0
Hello there!

Your question states: Xia has 16 meters of rope. She cuts off 1/6 of the rope to use as a skipping rope for a party activity. how long is xias skipping rope.

You can find this by doing the following:

16/ 1/6 = ?

how many times does 1/6 go into 16?

The answer is 2 and 2/3 meters or 8/3 meters or 2.66667 meters


Hope I helped!

Let me know if you need anything else!

~ Zoe





katrin2010 [14]3 years ago
6 0

\frac{1}{6}  \times 16 =  \frac{8}{3}  = 2.67m
So, Xia's skipping rope is 2.67m long.
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Find the time required for an investment of 5000 dollars to grow to 6000 dollars at an interest rate of 7.5 percent per year, co
sineoko [7]

2.5 years required for an investment of 5000 dollars to grow to 6000 dollars at an interest rate of 7.5 percent per year, compounded quarterly.

Step-by-step explanation:

The given is,

               Initial investment - $5000

               Future amount - $6000

               Interest rate - 7.5% (compounded quarterly)

Step:1

           Formula to calculate the Future amount with compound interest,

                                   F = P(1+\frac{r}{n} )^{nt}...................................(1)

          Where, F - Future amount

                           P - Initial amount

                            r - Rate of interest

                           n - No. of compounding in a year

                            t - Time period

          From given,

                      F = $6000

                      P = $5000

                       r = 7.5%

                       n = 4 (compounded quarterly)

        Equation (1) becomes,

                              6000=5000(1+\frac{0.075}{4} )^{(t)(4)}

                               \frac{6000}{5000} =(1+0.01875)^{4t}

                                 1.2 = (1.01875)^{4t}

         Take log on both sides,

                            log 1.2 = 4(t) log 1.01875

         Substitute log values,

                       0.07918 = 4(t) (0.0080676)

                                      = (t) (0.0322705)

                                   t = \frac{0.07918}{0.0322705}

                                      = 2.45

                                   t ≅ 2.5 years

Result:

         2.5 years required for an investment of 5000 dollars to grow to 6000 dollars at an interest rate of 7.5 percent per year, compounded quarterly.

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