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ad-work [718]
3 years ago
5

What is the polynomial function of lowest degree with lead coefficient 1 and roots i, –2, and 2?

Mathematics
1 answer:
elena-s [515]3 years ago
4 0

Answer:

I DONT UNDERSTAD THIS BUT IF YOU HAVE ANOTHER THING I CAN HELP YOU LET ME KNOW

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Figure out the pattern, and write the next number.<br> 2,6,21,88
bija089 [108]
Answer:
a5=445

Explanation:
a of n=(a+1)*n
a1=2
I found the pattern to add 1 to the previous number and then multiply it by its number in the sequence. Apologies for the terrible format of my recursive formula.
Proof of pattern:
(2+1)*2=6
(6+1)*3=21
(21+1)*4=88
a5=(88+1)*5=445
6 0
3 years ago
Let g be the function given by g(x)=x^2*e^(kx) , where k is a constant. For what value of k does g have a critical point at x=2/
ArbitrLikvidat [17]
G `( x ) =2x * e^{kx}  + k x^{2} *e^{kx} = \\  = xe^{kx}(2 + kx )
2 + k x = 0
k x = -2
k = -2: x = - 2 : 2/3 = - 2 * 3/2
k = - 3
Answer: for k= - 3, the function g ( x ) have a critical point at x = 2/3. 
8 0
3 years ago
3a = 18<br> (I know how to solve it, but how do I check my solution?)
qwelly [4]

Answer:

plug the a back in

3(6)=18 if the answer is 18 then your right

18=18

5 0
3 years ago
Read 2 more answers
Cane someone do this please
Jobisdone [24]

The product of the matrices is an identity matrix. Then Both the matrices are multiplicative inverse to each other.

<h3>What is the matrix?</h3>

A matrix is a specific arrangement of items, particularly numbers. A matrix is a row-and-column mathematical structure. The a_{ij} element in a matrix, such as M, refers to the i-th row and j-th column element.

The matrices are given below.

\left[\begin{array}{ccc}-3&7\\-2&5\end{array}\right] \  and \ \left[\begin{array}{ccc}-5&7\\-2&3\end{array}\right]

Then show that both the matrices are multiplicative inverse to each other.

If the product of the matrices is an identity matrix then the matrices are multiplicative inverse to each other.

Then we have

\left[\begin{array}{ccc}-3&7\\-2&5\end{array}\right]  \left[\begin{array}{ccc}-5&7\\-2&3\end{array}\right] = \left[\begin{array}{ccc}1&0\\0&1\end{array}\right]

Then both the matrices are multiplicative inverse to each other.

More about the matrix link is given below.

brainly.com/question/9967572

#SPJ1

4 0
3 years ago
Solve for x<br> (-7/6)x-6= -48<br> a36<br> b49<br> c-36<br> d-49
Marta_Voda [28]

Answer:

-7x/6-6=-48

-7x-36=-288

-7x=-288+36

x=-252/-7

x=36 answer

5 0
4 years ago
Read 2 more answers
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