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svetlana [45]
2 years ago
9

What is the value of (-12) 3 - 15?

Mathematics
2 answers:
Igoryamba2 years ago
8 0
The value of that is -51. -51 is the answer
Pani-rosa [81]2 years ago
5 0
Answer:
-51

Explanation:
(-12)3-15
1) Multiply -12 and 3
-36-15
2) Subtract-36 and 15
-51

I hope this helps! Please comment if you have any questions.
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A and B share the cost in a ratio of 3:2 A pays 125£ how much does b pay???
lana66690 [7]
Let the common multiple be x 
<span>3x : 2x </span>
<span>3x = 125 </span>
<span>x = 125/3 </span>

<span>So, B pays 2x = 2 × 125/3 = £250/3 </span>
8 0
2 years ago
Read 2 more answers
Help me problems! asap 1-7
Westkost [7]
Multiply the triangles then divide to find the missing number
7 0
3 years ago
If the circle below is cut from the square of plywood below, how many square inches of plywood would be left over? Use π = 3.14,
Elis [28]

Answer:

86in²

Step-by-step explanation:

Find the complete question attached

Area of the circle = πr²

Area of the square = L²

Length of the side of the square

r is the radius of the circle

r = L/2 = 20/2 =10in

Given

Length of the side of the circle = 20in

Area of the square = 20²

Area of the square = 400in²

Area of the circle =π(10)²

Area of the circle = 3.14(100)

Area of the circle= 314in²

Amount of plywood left over = 400in²-314in² = 86in²

8 0
2 years ago
"A cable TV company wants to estimate the percentage of cable boxes in use during an evening hour. An approximation is 20 percen
Marizza181 [45]

Answer:

The company should take a sample of 148 boxes.

Step-by-step explanation:

Hello!

The cable TV company whats to know what sample size to take to estimate the proportion/percentage of cable boxes in use during an evening hour.

They estimated a "pilot" proportion of p'=0.20

And using a 90% confidence level the CI should have a margin of error of 2% (0.02).

The CI for the population proportion is made using an approximation of the standard normal distribution, and its structure is "point estimation" ± "margin of error"

[p' ± Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }]

Where

p' is the sample proportion/point estimator of the population proportion

Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} } is the margin of error (d) of the confidence interval.

Z_{1-\alpha /2} = Z_{1-0.05} = Z_{0.95}= 1.648

So

d= Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }

d *Z_{1-\alpha /2}= \sqrt{\frac{p'(1-p')}{n} }

(d*Z_{1-\alpha /2})^2= \frac{p'(1-p')}{n}

n*(d*Z_{1-\alpha /2})^2= p'(1-p')

n= \frac{p'(1-p')}{(d*Z_{1-\alpha /2})^2}

n= \frac{0.2(1-0.2)}{(0.02*1.648)^2}

n= 147.28 ≅ 148 boxes.

I hope it helps!

3 0
3 years ago
Find the difference of 58.2–27.674.<br> a. 30.652<br> b. 30.526<br> c. 35.026<br> d. 35.620
d1i1m1o1n [39]

Answer:

B. 30.526

Step-by-step explanation:

Just subtract.

58.20

-27.674

30.526

7 0
3 years ago
Read 2 more answers
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