objective: central limit theorem assumptions. the factor(s) to be considered when assessing if the central theorem holds is/are

Mathematics

1 answer:

Eddi Din [679]3 years ago

8 0

Answer:

Sample size

Step-by-step explanation:

Central Limit Theorem states that population with mean and standard deviation and if the sample size is large then the distribution of sample mean will be will be normally distributed. The central limit theorem holds assumptions that the factors to be considered when assessing central limit theorem is sample size.

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larisa86 [58]

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4 years ago

suppose that y varies inversely with x, and y=3 when x=5. what is an equation for the inverse variation

Angelina_Jolie [31]

The inverse variation of y=3 would be y=1/3
The inverse variation of x=5 would be x=1/5

You just need to flip the variation around.

Your answer is: y=1/3; x=1/5

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3 years ago

What is the following simplified product? Assume

Yanka [14]

<u>Answer:</u>

The correct answer option is D. $10x^4\sqrt{6}+x^3\sqrt{30x}-10x^4\sqrt{3}-x^3\sqrt{15x}$ .

<u>Step-by-step explanation:</u>

We are given the following expression:

$\left ( \sqrt { 10 x ^ 4 } -x \sqrt { 5 x ^ 2 } \right ) \left ( 2 \sqrt { 15 x ^ 4 } + \sqrt { 3 x ^ 3 } \right )$

Assuming that $x\geq 0$ , we are to find its simplified product.

$\left ( \sqrt { 10 x ^ 4 } -x \sqrt { 5 x ^ 2 } \right ) \left ( 2 \sqrt { 15 x ^ 4 } + \sqrt { 3 x ^ 3 } \right )$

$\\\\ = 2 \sqrt { 150 x ^ 8 } + \sqrt { 3 0 x ^ 7 }-2x\sqrt{75x^6}-x\sqrt{15x^5} \\\\ =2\sqrt{25\times6x^8}+x^3\sqrt{30x}-2x\sqrt{25\times3x^6}-x^3\sqrt{15x} \\\\ =10x^4\sqrt{6}+x^3\sqrt{30x}-10x^4\sqrt{3}-x^3\sqrt{15x}$