All categories

3 years ago

objective: central limit theorem assumptions. the factor(s) to be considered when assessing if the central theorem holds is/are

Mathematics

1 answer:

Eddi Din [679]3 years ago

8 0

Answer:

Sample size

Step-by-step explanation:

Central Limit Theorem states that population with mean and standard deviation and if the sample size is large then the distribution of sample mean will be will be normally distributed. The central limit theorem holds assumptions that the factors to be considered when assessing central limit theorem is sample size.

You might be interested in

Find the equation of the line with slope = 2 and passing through (-3 , 4)

coldgirl [10]

Answer:

y = 2x + 10

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = 2. thus

y = 2x + c ← is the partial equation

To find c substitute (- 3, 4) into the partial equation

4 = - 6 + c ⇒ c = 4 + 6 = 10

y = 2x + 10 ← equation of line

8 0

3 years ago

Read 2 more answers

The difference of 13 and 5 times a number is 3.

Artemon [7]

Answer:

Step-by-step explanation:

13-5x =3

-13 -13

-5x = -10

-5 -5

x=2

3 0

3 years ago

Read 2 more answers

Branilest and 30 point please answer

Lynna [10]

Answer:

Addition Property of Equality

Step-by-step explanation:

System of Equations

When two equations are given and two variables are unknown in both equations, then we can solve the system in several ways.

One method consists in adding both equations term by term and eliminate one of the variables. That property is called the addition of equalities. Let's consider the equations given in the problem:

$5x+4y=-2\\2x-4y=6$

If we add both equations, we have

$5x+4y+2x-4y=-2+6$

Simplifying

$7x=4$

By adding both equations we managed to eliminate the variable y and could easily find the value of x

$x=4/7$

Answer: Addition Property of Equality

7 0

3 years ago

Use the definition of a Taylor series to find the first three non zero terms of the Taylor series for the given function centere

Ket [755]

Answer:

$e^{4x}=e^4+4e^4(x-1)+8e^4(x-1)^2+...$

$\displaystyle e^{4x}=\sum^{\infty}_{n=0} \dfrac{4^ne^4}{n!}(x-1)^n$

Step-by-step explanation:

Taylor series expansions of f(x) at the point x = a

$\text{f}(x)=\text{f}(a)+\text{f}\:'(a)(x-a)+\dfrac{\text{f}\:''(a)}{2!}(x-a)^2+\dfrac{\text{f}\:'''(a)}{3!}(x-a)^3+...+\dfrac{\text{f}\:^{(r)}(a)}{r!}(x-a)^r+...$

This expansion is valid only if $\text{f}\:^{(n)}(a)$ exists and is finite for all $n \in \mathbb{N}$ , and for values of x for which the infinite series converges.

$\textsf{Let }\text{f}(x)=e^{4x} \textsf{ and }a=1$

$\text{f}(x)=\text{f}(1)+\text{f}\:'(1)(x-1)+\dfrac{\text{f}\:''(1)}{2!}(x-1)^2+...$

$\boxed{\begin{minipage}{5.5 cm}\underline{Differentiating $e^{f(x)}$}\\\\If $y=e^{f(x)}$, then $\dfrac{\text{d}y}{\text{d}x}=f\:'(x)e^{f(x)}$\\\end{minipage}}$