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3 years ago

N Over 33 = 4 Over 11

Mathematics

1 answer:

raketka [301]3 years ago

5 0

Answer:

d. n = 12

Step-by-step explanation:

n/33 = 4/11

cross-multiply:

11n = 132

divide both sides by 11:

n = 12

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Separate 60 into two parts so that 3 times the smaller added to 6 more than 6 times the smaller = 60.

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3 years ago

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What’s the gradient and y intercept for c and e and could u explain pls thx

kifflom [539]

Step-by-step explanation:

if you are given an equation of a form y=kx+b, k is gradient and b is y-intercept

in c you can write this equation as y=(2x/3)-2,so gradient = 2/3 and y-intercept =-2

in e:6y=2x+3

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3 years ago

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What is the volume of the triangular prism? Round to the nearest tenth.

kramer

Answer:

the volume of the triangular prism is 1,185.6 in³

Step-by-step explanation:

To find the volume of these triangular prism, we will, first, find the area of the triangle then multiply by the length

Area of triangle = $\frac{1}{2}$ × b×h

From the diagram ,the height of the triangle is given to be 10.4 in and the base is given to be 12 in.

We will now proceed to insert the values into the formula;

Area of triangle = $\frac{1}{2}$ × b×h

= $\frac{1}{2}$ × 12×10.4

= $\frac{1}{2}$ × 124.8

=62.4

Area of triangle is 62.4 in²

From the diagram is given to be 19 in

Volume of triangular prism = area of triangular prism × l

=62.4 in² × 19 in

=1,185.6 in³

Therefore the volume of the triangular prism is 1,185.6 in³

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3 years ago

What's the answer to 1&2 plzz

Dmitrij [34]

1. 2880
2. 67%
Its simple math just put in effort

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3 years ago

Suppose f (x) = x^2. Find the graph of f(x+2)

NISA [10]

$\bf ~~~~~~~~~~~~\textit{function transformations}
\\\\\\
% templates
f(x)={{ A}}({{ B}}x+{{ C}})+{{ D}}
\\\\
~~~~y={{ A}}({{ B}}x+{{ C}})+{{ D}}
\\\\
f(x)={{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\\\
f(x)={{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\\\
f(x)={{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\\\\
--------------------$

$\bf \bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}\\
~~~~~~\textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }{{ B}}\textit{ is negative}\\
~~~~~~\textit{reflection over the y-axis}$

$\bf \bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
~~~~~~if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }{{ D}}\\
~~~~~~if\ {{ D}}\textit{ is negative, downwards}\\\\
~~~~~~if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}$

with that template in mind,

$\bf f(x)=x^2\qquad \quad f(x+2)=(x+2)^2\implies f(x+2)=\stackrel{A}{1}(\stackrel{B}{1}x\stackrel{C}{+2})^2\stackrel{D}{+0}$

C = 2 B = 1 C/B = 2/1 or +2, horizontal left shift of 2 units

f(x) shifted left by 2 units is f(x+2).

8 0

3 years ago