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Olegator [25]
3 years ago
9

Factor the polynomial 4x^4-20x^2-3x^2+15by grouping. Which is the resulting expression

Mathematics
2 answers:
Sindrei [870]3 years ago
5 0

Your answer appears to be (x^2-5)(4x^2-3) and heres why:

Steps\\$4x^4-20x^2-3x^2+15$\\\\Step 1. Factor 4x^4-20\\\\4x^4-20x^2\\\mathrm{Apply\:exponent\:rule}:\quad \:a^{b+c}=a^ba^c\\x^4=x^2x^2\\=4x^2x^2-20x^2\\\\\mathrm{Rewrite\:as}\\=4x^2x^2-5\cdot \:4x^2\\\\\mathrm{Factor\:out\:common\:term\:}4x^2\\=4x^2\left(x^2-5\right)\\\\$Step 2. \mathrm{Factor}\:-3x^2+15:\quad 3\left(-x^2+5\right)$\\-3x^2+15\\\\\mathrm{Rewrite\:as}\\=-3x^2+3\cdot \:5\\\\\mathrm{Factor\:out\:common\:term\:}3\\=3\left(-x^2+5\right)\\\\

Step\ 3.\\ $=4x^2\left(x^2-5\right)+3\left(-x^2+5\right)$\\\\\mathrm{Rewrite\:as}\\=4\left(x^2-5\right)x^2-3\left(x^2-5\right)\\\\\mathrm{Factor\:out\:common\:term\:}\left(x^2-5\right)\\=\left(x^2-5\right)\left(4x^2-3\right)

<h3>Now, if you have anymore questions and would like to see more answers like this, please make sure to Like, Comment, and Rate! Also, make sure to send me a friend request. I'm always up for a challenge!</h3><h2>Thanks!</h2>

ps. could you please mark me as Brainlyest? I kinda need it to help maintain and to reach the next rank... thx

Arisa [49]3 years ago
5 0

Answer:

\boxed{\bold{\left(x^2-5\right)\left(4x^2-3\right)}}

Step By Step Explanation:

Factor \bold{4x^4-20x^2}

\bold{4x^2\left(x^2-5\right)}

Factor \bold{-3x^2+15}

\bold{3\left(-x^2+5\right)}

Rewrite Equation

\bold{4x^2\left(x^2-5\right)+3\left(-x^2+5\right)}

Rewrite As...

\bold{4\left(x^2-5\right)x^2-3\left(x^2-5\right)}

Factor Out Common Term \bold{\left(x^2-5\right)}

\bold{\left(x^2-5\right)\left(4x^2-3\right)}

\boxed{\bold{\black{Mordancy}}}

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Let value intially be = P

Then it is decreased by 20 %.

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Similarly for 2nd year, this value 0.8P will again be decreased by 20 %

so 20% of 0.8P = \frac{20}{100} \times 0.8P = (0.2)(0.8P)

So after 2 years value is decreased by (0.2)(0.8P)

so value after 2 years will be = 0.8P - 0.2(0.8P)

taking 0.8P common out we get 0.8P(1-0.2)

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Similarly after 3 years, this value P(0.8)^{2} will again be decreased by 20 %

so 20% of P(0.8)^{2}  \frac{20}{100} \times P(0.8)^{2} = (0.2)P(0.8)^{2}

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so value after 3 years will be = P(0.8)^{2}   - (0.2)P(0.8)^{2}

taking P(0.8)^{2} common out we get P(0.8)^{2}(1-0.2)

P(0.8)^{2}(0.8)

P(0.8)^{3}-----------------------(3)

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value after 1 year is P(0.8) or P(0.8)^{1}

value after 2 years is P(0.8)^{2}

value after 3 years is P(0.8)^{3}

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