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Galina-37 [17]
3 years ago
14

Find the area of an equilateral triangle (regular 3-gon) with the given measurement of 6 inch side

Mathematics
1 answer:
Anton [14]3 years ago
6 0

\bf \textit{area of an equilateral triangle}\\\\ A=\cfrac{s^2\sqrt{3}}{4}~~ \begin{cases} s=length~of\\ \qquad a~side\\[-0.5em] \hrulefill\\ s=6 \end{cases}\implies A=\cfrac{6^2\sqrt{3}}{4}\implies A=9\sqrt{3}

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6 * [5 * (3 - 9) - 1] + 2 / 7 * (8 - 2) + 4 = 6 * [5 * (-6) - 1] + 2/7 * 6 +  4 = 6 * [- 30 - 1] + 12/7 + 4 = 6 * [- 31] + 12/7 + 4 = - 186 + 12/7 + 4 = - 182 + 12/7 = - 1274/7 + 12/7 = - 1262/7

The correct result would be - 1262/7.
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