Find the area of an equilateral triangle (regular 3-gon) with the given measurement of 6 inch side

1 answer:

6 0

$\bf \textit{area of an equilateral triangle}\\\\ A=\cfrac{s^2\sqrt{3}}{4}~~ \begin{cases} s=length~of\\ \qquad a~side\\[-0.5em] \hrulefill\\ s=6 \end{cases}\implies A=\cfrac{6^2\sqrt{3}}{4}\implies A=9\sqrt{3}$

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