Question

If triangle abc is similar to triangle def with ab=9, bc=11, and ac=16, then which of the following is closest to the ratio of de to df?

Answer 1

Answer:

$\frac{de}{df}=\frac{9}{16}$  or $\frac{de}{df}=0.5625$

Step-by-step explanation:

we know that

If two figures are similar, then the ratio of its corresponding sides is proportional

so

In this problem

Triangle abc is similar to Triangle def

therefore

$\frac{de}{df}=\frac{ab}{ac}$

substitute the given values

$\frac{de}{df}=\frac{9}{16}$