Answer:
the degree to which they decrease CNS activity
Explanation:
Drugs can be classified as;
✓hallucinogens, example is (LSD)
✓ stimulants, example is (cocaine)
✓opium-related painkillers example is (heroin)
✓depressants
Depressants can be regarded as medicines, that lowers neurotransmission levels, that is depressing or reducing arousal or stimulation as regards to various areas of the brain. these could be tranquilizers, as well as hypnotics and
sedatives. They are drugs used in slowing brain activity, therefore, making them useful when treating anxiety, sleep disorders, panic and acute stress reactions.
Example of Depressants are;
✓Xanax
✓Halcion
✓Klonopin
✓Librium
It should be noted that Depressants are often classified according to the degree to which they decrease central nervous system (CNS) activity.
Answer:
oh thats a bomb song tho i love
Answer:
a.Carbon :proton number =6
electron number =6
b. Fluorine: proton number=9
electron number =9
c. tin: proton number=50
electron number =50
d. nickel:proton number=28
electron number =28
Explanation:
In the neutral state of an atom the number of protons is always equal to the number of electrons and that whats makes it electrically neutral as the positive charges of protons balances the negative charges of electrons.
P has five electrons, three available to share. Since Cl has seven valence electrons, it can take on one more to accomplish an octet. In PCl3, P’s three valence electrons are evenly distributed among the three chlorine atoms. Whereas, in PCl5 there will be two electrons left over, which is why it is an exception to the octet rule.
<span>3 ZnBr2 (aq) + 2 Al (s) ==> 2 AlBr3 (aq) + 3 Zn (s)
The unbalanced equation is:
ZnBr2 (aq) + Al (s) ==> AlBr3 (aq) +Zn (s)
First, count the atoms of each element on each side of the equation:
Zn 1,1
Br 2,3
Al 1,1
The zinc and aluminum, but the bromine doesn't match with 2 and 3. So look for the least common multiple of 2 and 3 which is 6 and adjust the quantities on both sides to have 6 bromine atoms on both sides. Do this by having 3 zinc bromide on the left and 2 aluminum bromide on the right, getting:
3 ZnBr2 (aq) + Al (s) ==> 2 AlBr3 (aq) +Zn (s)
Now check the atom counts again for both sides:
Zn 3,1
Br 6,6
Al 1,2
Now bromine matches, but zinc and aluminum doesn't. But it's easy enough to add an extra aluminum to the left and 2 more zinc to the right. Giving:
3 ZnBr2 (aq) + 2 Al (s) ==> 2 AlBr3 (aq) + 3 Zn (s)
Now check the atom counts again:
Zn 3,3
Br 6,6
Al 2,2
And they match. So the balanced equation is:
3 ZnBr2 (aq) + 2 Al (s) ==> 2 AlBr3 (aq) + 3 Zn (s)</span>
