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Pie
4 years ago
7

Which electron configuration represents a Scandium atom?

Chemistry
1 answer:
VARVARA [1.3K]4 years ago
4 0
Sc (neutral) [Ar] 3d1 4s2
Sc+ [Ar] 3d1 4s1
Sc2+ [Ar] 3d1
hope this helped!
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I WILL GIVE BRAINLIEST
juin [17]

Answer:

Volumes can have the same volume but different masses if they have different densities. For example, a 10 x 10 x 10 block of lead has the same volume as a 10 x 10 x 10 block of pine wood, but the lead block weighs 22.6 times more than the pine block. Indeed, the density of lead is high enough that the lead block will sink in water, whereas the pine block's density is low enough that the pine block will float in water.

Volume is a measurement, the units are cubic metres or cubic centimetres. Litres = 1000 cm3

Mass is a measurement, the units are grams, kilograms.

^^^^^^^^^^^^^^^^^^

to that answer.

Mass is not weight. it is the amount of matter an object takes up. Therefore, saying that a lead block weights 22.6 times more than the pine block does not answer how an object can have different masses but the same volume. :D

5 0
3 years ago
How many liters are in 555 g of O2
victus00 [196]

Answer:

388.5

Explanation:

\frac{555}{32}  = 17.34375 \\ 17.34375  \times 22.4 = 388.5

3 0
4 years ago
How does a fire blanket work?​
Anika [276]

Answer:

Fire blankets are powerful pieces of equipment which work by cutting off the oxygen supply of a fire, thereby starving it of one of the three crucial elements it needs to survive and ultimately extinguishing it.

5 0
3 years ago
Read 2 more answers
Help please chemistry sucks ;(
ElenaW [278]
3.50g H2:

3.50g H2 x 1 mol H2 / 2(1.01gH2)= 1.7675mol H2
- the grams cancel out
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4 0
3 years ago
A sample of helium gas has a pressure of 1.5 atm at 23 C. At what Celsius
Nina [5.8K]

Answer:

180.87 °C

Explanation:

Applying pressure law,

P/T = P'/T'..................... Equation 1

Where P = Initial pressure of helium gas, T = Initial Temperature of helium gas, P' = Final Pressure of helium gas, T' = Final Temperature of helium gas

Make T' the subject of equation 1

T' = P'T/P......................... Equation 2

From the question,

Given: P = 1.5 atm, P' = 2.3 atm, T = 23°C = (23+273)K = 296 K

Substitute these values into equation 2

T' = (2.3×296/1.5)

T' = 680.8/1.5

T' = 453.87 K

T' = 453.87-273

T' = 180.87°C

3 0
3 years ago
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