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Nitella [24]
3 years ago
7

How many p orbitals are filled in fluorine?

Chemistry
1 answer:
DENIUS [597]3 years ago
7 0
I believe the answer is 2
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The process of converting nitrogen into nitrogen compounds by bacteria is called:
7nadin3 [17]
I believe this process is called fixation
7 0
4 years ago
Ce procent de impuritati contine un minereu de siderit, daca din 1500kg minereu s-au obtinut 700kg fier 90% ?
Pachacha [2.7K]

FeCO3  ==> Fe + produsi minoritari.


m Fe impur= 700 kg


puritatea (p) = masa pura (mp)/ masa impura (mi) x 100

mp= p x mi / 100 sau mp = p/100 x mi => mp Fe = 90/100 x 700 = 630 kg Fe pur.


M FeCO3= 115.85 kg/kmol

115.85 kg FeCO3 .... 55.85 kg Fe

     x kg FeCO3  ........630 kg Fe

x= 630 * 115.85 /55.85 = 1306.81 kg FeCO3 (mp in formula puritatii)

p=mp/mi x 100

mi FeCO3 = 1500 kg

mp FeCO3=1306.81 kg

p=1306.81 / 1500 x 100 = 87.12% puritate Siderit




8 0
3 years ago
A nuclear fission reaction has mass difference between the products and the reactants of 3.86 g. Calculate the amount of energy
iris [78.8K]

<u>Answer:</u> The amount of energy released by the reaction is 3.47\times 10^{14}J

<u>Explanation:</u>

To calculate the energy released, we use Einstein equation, which is:

E=\Delta mc^2

where,

\Delta m = difference between the masses of products and reactants = 3.86 g = 0.00386 kg    (Conversion factor: 1 kg = 1000 g)

c = speed of light = 3\times 10^8m/s

Putting values in above equation, we get:

E=(3.86\times 10^{-3}kg)\times (3\times 10^8m/s)^2

E=3.47\times 10^{14}J

Hence, the amount of energy released by the reaction is 3.47\times 10^{14}J

3 0
3 years ago
The probability?????????????????
olga55 [171]
Answer: 4/20

Explanation:
7 0
3 years ago
How many atoms would be contained in 549 grams of zinc
gizmo_the_mogwai [7]

Answer:

                       5.05 × 10²⁴ Zn Atoms

Explanation:

                    In order to find the number of atoms we will follow these two steps;

Step 1:  <u>Finding out the moles of Zn as;</u>

Moles  =  Mass / A. Mass

Moles  =  549 g / 65.38 g/mol

Moles  =  8.397 moles

Step 2: <u>Calculating No. of Atoms as:</u>

According to Avogadro's Law, each mole contains 6.022 × 10²³ particles. These particles can be any entity i.e. atoms, molecules, formula units, ions e.t.c. So,

No. of Atoms  =  Moles × 6.022 × 10²³ atoms/mol

No. of Atoms  =  8.397 mol × 6.022 × 10²³ atoms/mol

No. of Atoms  =  5.05 × 10²⁴ Zn Atoms

7 0
3 years ago
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