Answer:
The answer is A. -4.
Step-by-step explanation:
The missing value you are looking for is the y-intercept or where the line crosses the y axis.
Answer:
Step-by-step explanation:
this idea is probably a good thing to have a solid understand of. That Cartesian (rect) is the x and y components, of the legs of a triangle and is a way to measure that part of the two leg of the triangle that is made up by those pieces.. while the polar system would measure the hypotenuse of that same triangle with the degrees as a way to place where that hypotenuses goes
the abs value of an imaginary number will give you that distance from the origin to the point.. if you are using that sqrt (
+
) to get the abs. this is the same as the magnitude and can represent a total force. The distance between the origin and the point is that idea of two points.. conveniently we used (0,0) the origin as one of the points.. the other is at the top of the line or the point given by the complex number
Hopefully that helps... :/
(6+6+6)(36+1) = (18)(37) = 666. ... If you don't want an answer posted, there's a simple solution ... don't post the question ! And if it still mysterously somehow appears, then for heaven's sake, don't offer points as a reward for an answer. ... Finally ... devil's numbers belong in the Old Wives' Hooey category, not in the Mathematics one. They're not real.
The coordinates of B' are 3 and -12. so option D is correct (3, -12)
<h3>How to find the coordinates of B'?</h3>
The point P(x, y) may undergo translation to form P' by using a defined translation rule :
If given the rule T(a, b) synch that P undergoes translation on T; then we will have P'(x+a; y+b)
Therefore,
The point B has its coordinates as B(1, - 5)
Translation rule, T(2, - 7) then the coordination of B after undergoing transformation according to T2;
B(1, - 5) - - - > T(2, - 7) - - - - > B'(1+2 ; - 5+-7)
= B'(3, -12)
Hence, the coordinates of B' are 3 and -12. so option D is correct.
Learn more about the concept :
brainly.com/question/12463306
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Answer should be
|-80-15| or
|15-(-80)|