Let a = 693, b = 567 and c = 441
Now first we will find HCF of 693 and 567 by using Euclid’s division algorithm as under
693 = 567 x 1 + 126
567 = 126 x 4 + 63
126 = 63 x 2 + 0
Hence, HCF of 693 and 567 is 63
Now we will find HCF of third number i.e., 441 with 63 So by Euclid’s division alogorithm for 441 and 63
441 = 63 x 7+0
=> HCF of 441 and 63 is 63.
Hence, HCF of 441, 567 and 693 is 63.
X would be 0 while Y would be 4
3x+y=4
-(2x+y=4)
----------------
x=0
Plug in x to any of those two equations in their original form
3(0)+y=4
0 + y = 4
y = 4
A) 8^2 + 12^2=c^2
c= 4(13) or 14.42
B) 8^2 + b^2=12^2
b=4(5) or 8.94
The angle at the center of the circle is twice the angle at the circumference.
<h3>What is Circle Theorem?</h3>
The angle in a semicircle is a right angle. Angles that are in the same segment are equal.
As by theorem,
angle in a semicircle is a right angle. Angles that are in the same segment are equal.
Also, opposite angle in a cyclic quadrilateral sums to 180° and the angle between the chord and tangent is also equal to the angle in the alternate segment.
Learn more about circles here:
brainly.com/question/24375372
#SPJ1
