Question

Help please if ur good at math

Answer 1

Part (a)

  $\int\limits^6_0 {f(x)} \, dx =\int\limits^3_0 {f(x)} \, dx +\int\limits^6_3 {f(x)} \, dx =8+(-7) = 1$

Part (b)

 $\int\limits^3_6 {f(x)} \, dx =-\int\limits^6_3 {f(x)} \, dx =-(-7) = 7$

Part (c)

$\int\limits^3_3 {f(x)} \, dx =0$

Part (d)

$\int\limits^6_3 {-5f(x)} \, dx =-5* \int\limits^6_3 {f(x)} \, dx=-5 * -7 =35$

Hope that helps!