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Rudiy27
3 years ago
9

Construct a perpendicular bisector to AB.

Mathematics
1 answer:
monitta3 years ago
6 0

Answer:

Take a fixed gap and draw 180 degree arc of equal size on each side.

The compass size should be the same for the whole process, be careful.

Make 90 degrees angle for both side and cross two arcs from each 90 degrees. The point thus obtained should be produced vertically towards the line AB. The point on the line segment is the line bisector.

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Write the equation of the line shown in point-slope form. (2,1) (3,8)
Ulleksa [173]

<u>Answer:</u>

The line equation that passes through the given points is 7x – y = 13

<u>Explanation:</u>

Given:

Two points are A(2, 1) and B(3, 8).

To find:

The line equation that passes through the given two points.

Solution:

We know that, general equation of a line passing through two points (x1, y1), (x2, y2) in point slope form is given by

\frac{(y- y1)}{(x-x_1)}= \frac{((y_2- y_1)}{(x_2- x_1 )}

{(y- y1)= \frac{((y_2- y_1)}{(x_2- x_1 )}\times(x-x_1)..........(1)

here, in our problem x1 = 3, y1 = 8, x2 = 2 and y2 = 1.

Now substitute the values in (1)

(y-8) = \frac{(1 - 8)}{(2 - 3)}\times(x- 3)

(y -8) = \frac{(- 7)}{(-1)}(x-3)

y – 8 = 7(x – 3)

y – 8 = 7x – 21  

7x – y = 21 – 8  

7x – y = 13  

Hence, the line equation that passes through the given points is 7x – y = 13

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Step-by-step explanation:

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