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2 years ago

Best tip for Maths test to figure out challenging problems

Mathematics

1 answer:

padilas [110]2 years ago

3 0

First solve the easier questions which can be solved in very low time.
Drop out the harder questions for last.
After completing the easier questions take your time to complete harder ones.
Stay away from unsolvable questions

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Suppose that replacement times for washing machines are normally distributed with a mean of 9.3 years and a standard deviation o

Ad libitum [116K]

The probability will be found as follows:
z-score is given by:
z=(x-μ)/σ
where:
mean-μ=9.3
standard deviation-σ=1.1
but
σ/√n=1.1/√70=0.1315
thus the z-score will be:
z=(9.1-9.3)/0.1315
z=-1.5209
thus:
P(x<9.1)=P(z<-1.5209)=0.0643

7 0

3 years ago

Jeremy wants to construct an open box from an 18-inch square piece of aluminum. He plans to cut equal squares, with sides of x i

serious [3.7K]

The volume of the box V = 4x³ - 72x² + 324x

Since the dimensions of the square piece of paper are 18 inches each, and we cut out a length x from each side to give a total length of 2x cut from each side. So, each dimension is L = 18 - 2x.

Since the height of the open box is x and its base is a square, the volume of the open box ix V = L²x

= (18 - 2x)²x

= (324 - 72x + 4x²)x

= 324x - 72x² + 4x³

The volume of the box V = 4x³ - 72x² + 324x

The minimum value of length of the sides of the squares cut from each corner is x = 3 inches.

the length of the box, L = 12 inches,
the width of the box = 12 inches
and the height of the box, x = 3 inches.

Since the volume of the box is 432 cubic inches,

V = 324x - 72x² + 4x³

324x - 72x² + 4x³ = 432

4x³ - 72x² + 324x - 432 = 0

x³ - 18x² + 81x - 108 = 0

A factor of the expression is x - 3

So, x³ - 18x² + 81x - 108 ÷ x - 3 = x² - 15x + 36

So, x³ - 18x² + 81x - 108 = (x² - 15x + 36)(x - 3) = 0

Factorizing the expression x² - 15x + 36 = 0

x² - 3x - 12x + 36 = 0

x(x - 3) - 12(x - 3) = 0

(x - 3)(x - 12) = 0

So, x³ - 18x² + 81x - 108 = (x - 3)(x - 3)(x - 12) = 0

So, (x - 3)²(x - 12) = 0

(x - 3)² = 0 and (x - 12) = 0

x - 3 = √0 and x - 12 = 0

x - 3 = 0 and x - 12 = 0

x = 3 twice and x = 12

Since x = 3 is the minimum value, the minimum value of x = 3.

Since the length of the box, L = 18 - 2x

= 18 - 2(3)

= 18 - 6

= 12 inches

The width of the box = L = 12 inches

The height of the box = x = 3 inches.

So,

The minimum value of length of the sides of the squares cut from each corner is x = 3 inches.

the length of the box, L = 12 inches,
the width of the box = 12 inches
and the height of the box, x = 3 inches.

Learn more about volume of a box here:

brainly.com/question/13309609

6 0

1 year ago

Mr. Frankel bought 7 tickets to a puppet show and spent $43. He bought a combination of child tickets for $4 each and adult tick

pav-90 [236]

A + C = 7
$9(A) + $4(C) = $43

8 0

3 years ago

Read 2 more answers

Two different floor plans are being offered in a new housing development. Several prospective

cricket20 [7]

Answer:

0.912

Step-by-step explanation:

<em>The complete question is attached.</em>

<em />

"OR" in probability means "ADDITION". So we find the individual probabilities and "ADD" them.

P(Plan A) would be the total people for plan A (add up column of Plan A) divided by total number of people [add up all the numbers].

Looking at the table, we have:

P (Plan A) = 38/68

Now,

P(40-49 Group) can be found by adding up the row of 40-49 age group and dividing by the total. So, we have:

P(40 - 49 Group) = 24/68

Now, adding up both:

38/68 + 24/68 = 62/68 = 0.912

7 0

2 years ago

Make m the subject in a(c+m)=2(c+3m)

Murrr4er [49]

Answer:

m = $\frac{2c-ac}{a-6}$

Step-by-step explanation:

distribute parenthesis on both sides

ac + am = 2c + 6m ( collect terms in m on left side )

subtract 6m from both sides

ac + am - 6m = 2c ( subtract ac from both sides )

am - 6m = 2c - ac ( factor left side )

m(a - 6) = 2c - ac ( divide both sides by (a - 6))

m = $\frac{2c-ac}{a-6}$

3 0

3 years ago

Best tip for Maths test to figure out challenging problems​

Best tip for Maths test to figure out challenging problems