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goldenfox [79]
3 years ago
13

Best tip for Maths test to figure out challenging problems​

Mathematics
1 answer:
padilas [110]3 years ago
3 0
  • First solve the easier questions which can be solved in very low time.
  • Drop out the harder questions for last.
  • After completing the easier questions take your time to complete harder ones.
  • Stay away from unsolvable questions
You might be interested in
The three sides of a triangle are (x+5)cm ,(2x+4)cm and (2x-3)cm .
natali 33 [55]

Hey ! there

Answer:

  • <u>a.</u> Perimeter = <u>(</u><u> </u><u>5</u><u>x</u><u> </u><u>+</u><u> </u><u>6</u><u> </u><u>)</u><u> </u><u>cm</u>

  • <u>b.</u> Perimeter when x is equal to 10 = <u>56 cm</u>

Step-by-step explanation:

In this question we are given with three sides of a triangle that are as follows ,

  • <u> </u><u>(</u><u> </u><u>x </u><u>+</u><u> </u><u>5</u><u> </u><u>)</u><u> </u><u>cm</u>

  • <u> </u><u>(</u><u> </u><u>2</u><u>x</u><u> </u><u>+</u><u> </u><u>4</u><u> </u><u>)</u><u> </u><u>cm</u>

  • <u> </u><u>(</u><u> </u><u>2</u><u>x</u><u> </u><u>-</u><u> </u><u>3 </u><u>)</u><u> </u><u>cm</u>

And we are asked to :

  • <u>a.</u><u> </u><u>find </u><u>perimeter</u><u> of</u><u> </u><u>triangle</u><u>. </u>

  • <u>b.</u><u> </u><u>find </u><u>perimeter</u><u> </u><u>if </u><u>x </u><u>is </u><u>equal </u><u>to </u><u>1</u><u>0</u><u> </u><u>.</u>

We know that for finding perimeter of any shape we must have to add all the sides of the shape or ,

\qquad \:    \underline{\boxed{\frak{Perimeter = Sum  \: of  \: all  \: sides}}}

<u>Solution</u><u> </u><u>:</u><u> </u><u>-</u>

<u>(</u><u> </u><u>a </u><u>)</u>

Now adding all the three sides of triangle to find the perimeter .

\hookrightarrow \quad \: ( x + 5 ) + ( 2 x + 4 ) + ( 2x - 3 )

\hookrightarrow \quad \: \: x + 5 + 2x + 4 + 2x - 3

Combining like terms :

\hookrightarrow \quad \:x + 2x + 2x + 5 + 4 - 3

Now , solving :

\hookrightarrow   \quad \: \red{\underline{ \boxed{ \frak{(5x + 6) \: cm}}}}

  • <u>Therefore</u><u> </u><u>,</u><u> </u><u>perimeter</u><u> </u><u>of</u><u> </u><u>triangle </u><u>is </u><em><u>5</u><u>x</u><u> </u><u>+</u><u> </u><u>6</u><u> </u></em><em><u>centi</u></em><em><u>metres </u></em><em><u>.</u></em>

<u>(</u><u> </u><u>b </u><u>)</u>

Now , we are finding perimeter of triangle when value of x is <u>1</u><u>0</u><u> </u><u>.</u><u> </u>So substituting value of x in given sides of triangle ,

First Side :

  • x + 5

  • 10 + 5

  • <u>1</u><u>5</u><u> </u><u>cm</u>

<u>Second</u><u> </u><u>Side </u>:

  • 2x + 4

  • 2 ( 10 ) + 4

  • 20 + 4

  • <u>2</u><u>4</u><u> </u><u>cm</u>

Third Side :

  • 2x - 3

  • 2 ( 10 ) - 3

  • 20 - 3

  • <u>1</u><u>7</u><u> </u>

<u>So </u><u>,</u><u> </u><u>all </u><u>the </u><u>sides </u><u>are </u><u>1</u><u>5</u><u> </u><u>cm </u><u>,</u><u> </u><u>2</u><u>4</u><u> </u><u>cm </u><u>and </u><u>1</u><u>7</u><u> </u><u>cm </u><u>.</u>

<u>Now </u><u>,</u><u> </u><u>adding</u><u> </u><u>all </u><u>these </u><u>to </u><u>find </u><u>perimeter</u><u> </u><u>.</u><u> </u>

<u>\hookrightarrow \qquad \: 15 + 24 + 17</u>

<u>\hookrightarrow \qquad \: 39 + 17</u>

<u>\hookrightarrow \qquad \:    \red{\underline{\boxed{\frak{56 \: cm}}}}</u>

  • <u>Therefore</u><u> </u><u>,</u><u> </u><u>perimeter</u><u> </u><u>of </u><u>triangle </u><u>when </u><u>value </u><u>of </u><u>x </u><u>is </u><u>1</u><u>0</u><u> </u><u>cm </u><u>is </u><em><u>5</u></em><em><u>6</u></em><em><u> </u></em><em><u>cm </u></em><em><u>.</u></em>

<u>Alternative</u><u> </u><u>Solution</u><u> </u><u>:</u><u> </u><u>-</u>

As above we have find the perimeter of triangle in term of x that is ( <u>5</u><u>x</u><u> </u><u>+</u><u> </u><u>6</u><u> </u><u>)</u><u> </u><u>cm.</u><u> </u><u>So</u> we can put value of x as 10 in this to get perimeter. So ,

  • 5x + 6

  • 5 ( 10 ) + 6

  • 50 + 6

  • <u>56 </u><u>cm</u>

<u>Therefore</u><u>,</u><u> </u><u>perimeter</u><u> </u><u>of </u><u>triangle</u><u> </u><u>is </u><u>5</u><u>6</u><u> </u><u>cm </u><u>.</u>

<h2><u>#</u><u>K</u><u>e</u><u>e</u><u>p</u><u> </u><u>Learning</u></h2>
4 0
2 years ago
Read 2 more answers
The circumference is 9.42 cm.
ehidna [41]
So the circumference is 9.42 then 91/9.42 = about 9
4 0
3 years ago
Sally had 24 apples,she wanted to put all the apples in 4 bags.How many apples
vazorg [7]
If she has 4 bags and 24 apples, we can do 24/4 to find out that 6 apples would go in each bag

Hope this helps
5 0
4 years ago
PLEASE HELP ME I WILL MARK BRAINLIEST!!!!! point X is located at (3,2). Point Y is located at (3,-8).
vovikov84 [41]

Answer:

Point X is 10 units above Point Y or (X,Y-10)=Y

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
George has a triangle-shaped garden in his backyard. He drew a model of this garden on a coordinate grid with vertices A(4, 2),
oksian1 [2.3K]
Given:

Vertices of a triangular garden:

A(4,2)
B(2,4)
C(6,4)
Scale factor = 0.5

Find the distance between points:

d = √(x2-x1)^2 + (y2-y1)^2

dAB = 2√2
dBC = 4
dCA = 2√2

A similarly shaped garden is to be created using the scale factor, 0.5:

A' = 2√2 / 0.5 = 4√2
B' = 4 / 0.5 = 8
C' = 2√2 / 0.5 = 4√2 
6 0
3 years ago
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