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gavmur [86]
3 years ago
12

Which is a counterexample for the following statement?

Mathematics
2 answers:
Digiron [165]3 years ago
7 0
Answer :
2 and 8
1 and 3
lakkis [162]3 years ago
4 0

Answer:

2 and 8

1 and 3

Step-by-step explanation:

statement a+b < a*b

-2 + -8 < -2 * -8 => -10 < 16 TRUE

-1 + -3 < -1 * -3 => -4 < 3 TRUE

1+3 < 1*3 => 4 < 3 FALSE

2 + 8 < 2 * 8 => 10 < 16 FALSE

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Semmy [17]

Answer:

Step-by-step explanation:

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6 0
2 years ago
How should the decimal point in 34.05 be moved to determine the product 34.05×106 ?
r-ruslan [8.4K]

Answer: Six places to the right

Step-by-step explanation:

For this exercise it is important to remember that. by definition, the exponent of a number indicates the number of times you must use the same factor to multiply.

Given:

b^n

"b" is the base and "n" is the exponent.

In this case, you have the following multiplication provided in the exercise:

34.05*10^6

Notice that the base 10 has an exponent 6. This indicates the following:

10^6=10*10*10*10*10*10=1,000,000

By definition, moving the decimal point 6 places to the right (because there are six zeros), is the same as multiplying the decimal number 34.05 by 1,000,000.

  Therefore, based on the explained, when you move the decimal point six places to the right, you get the following product.

34.05*10^6=34,050,000

3 0
3 years ago
Are the ratios 3:6 and 6:3 equivalent?
Hunter-Best [27]

Answer: No

Step-by-step explanation: the ratio 3:6 reduces to one half

the ratio 6:3 reduces to 2 because division cannot be interchangeable

4 0
3 years ago
What is the value of the fourth term in a geometric sequence for which a1 = 30 and r = 1/2?
Pani-rosa [81]

Answer:  The required fourth term of the geometric sequence is \dfrac{10}{9}.

Step-by-step explanation:  We are given to find the value of the fourth term in a geometric sequence with first term and common ratio as follows :

a(1)=30,~~~~~r=\dfrac{1}{2}.

We know that

the n-th term of a geometric sequence with first term a1 and common ratio r given by

a(n)=a(1)r^{n-1}.

Therefore, the fourth term of the given geometric sequence will be

a(4)=a(1)r^{4-1}=30\times r^3=30\times\left(\dfrac{1}{3}\right)^3=\dfrac{30}{27}=\dfrac{10}{9}.

Thus, the required fourth term of the geometric sequence is \dfrac{10}{9}.

7 0
3 years ago
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Zielflug [23.3K]
1 board that is 10 feet long and make that into 6 table legs. Take the amount we have over the amount we want, so 10 over 6 which is 1.6666667 feet which is the longest each leg can be for a 10-foot board.
3 0
3 years ago
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