Answer:
a. The first six terms are:
-7, -4, -1, 2, 5, 8
b. The first six terms are:
0, 2, 0, 2, 0, 2.
c. The first six terms are:
4, 8, 24, 96, 480, 2880
Step-by-step explanation:
a. an - 3n - 10
For n = 1
a1 = 3(1) - 10
= -7
For n = 2
a2 = 3(2) - 10
= -4
For n = 3
a3 = 3(3) - 10
= -1
For n = 4
a4 = 3(4) - 10
= 2
For n = 5
a5 = 3(5) - 10
= 5
For n = 6
a6 = 3(6) - 10
= 8
The first six terms are:
-7, -4, -1, 2, 5, 8
b. an= (1+(-1)^n)^n
For n = 1
a1 = (1+(-1)^1)^1
= 0
For n = 2
a2 = (1+(-1)^2)^1
= 2
For n = 3
a3 = (1+(-1)^3)^1
= 0
For n = 4
a4 = (1+(-1)^4)^1
= 2
For n = 5
a5 = (1+(-1)^5)^1
= 0
For n = 6
a6 = (1+(-1)^6)^1
= 2
The first six terms are:
0, 2, 0, 2, 0, 2.
c. an= 2n! (2)
For n = 1
a1 = 2(1!)(2)
= 4
For n = 2
a2 = 2(2!)(2)
= 8
For n = 3
a3 = 2(3!)(2)
= 24
For n = 4
a4 = 2(4!)(2)
= 96
For n = 5
a5 = 2(5!)(2)
= 480
For n = 6
a6 = 2(6!)(2)
= 2880
The first six terms are:
4, 8, 24, 96, 480, 2880
Step-by-step explanation:
set o= o
set t= t
those are the set of letters used to form the set
Answer:
Sorry Iam at exam now
I know the answer but IAM writing exam
Area of circle = πr² = 3.14×4² = 50.24m²
The best approximation is C.
