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2 years ago

6

Find the amount of sap the maple syrup producer would have collected from each tree if the total amount if the total amount is (

5gallons) was redistributed equally among trees

2 answers:

kvv77 [185]2 years ago

5 0

There are 10 crosses, which means that there are 10 trees in total. If we distribute 5 gallons among 10 trees, we give each tree

5/10=1/2=0.5 gallons

kherson [118]2 years ago

3 0

Answer:

Each tree will get 0.5 gallons of Syrup redistributed to it.

Step-by-step explanation:

According to the line graph shown in the picture there are 10 trees in total. We have 5 gallons of syrup that needs to be distributed <u>equally</u> among all ten trees. We can solve this by simply dividing the amount of syrup by the amount of trees that will be sharing the syrup.

5/10 = 0.5 gallons each

So each tree will get 0.5 gallons of Syrup redistributed to it.

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

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Is (4,3) a solution to the inequality graph below? Why or why not? I need help plz don’t upload files

Studentka2010 [4]

Answer:

yes

Step-by-step explanation:

Go to x=4 and y= 3

It is in the shaded area to it is a solution

7 0

2 years ago

The volume of the cube below is 1/8cm^2 . What is the value of x?

Kipish [7]

We are given

edge of cube =x

we know that formula for volume of cube

$V=x^3$

we are given

$V=\frac{1}{8} cm^3$

we can plug value

$x^3=\frac{1}{8} cm^3$

now, we can solve for x

$\sqrt[3]{x^3} =\sqrt[3]{\frac{1}{8} cm^3 }$

$x=\frac{1}{2} cm$ ............Answer

6 0

3 years ago

Read 2 more answers

0.5 kilograms is equal to how many grams

____ [38]

Answer:

500 grams.

Step-by-step explanation:

1kg = 1000grams.

0.5 * 1000 = 500grams.

8 0

2 years ago

Read 2 more answers

Please help thanks very much

olchik [2.2K]

A)
sinA = 8√3 / 16 = √3 / 2

answer is B
√3 / 2

B) It's 30 60 90 right triangle
so <B is 30

answer is A
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6 0

2 years ago

Consider a rabbit population P(t) satisfying the logistic equation StartFraction dP Over dt EndFraction equals aP minus bP squa

maria [59]

Solution:

Given :

$\frac{dP}{dt}= aP-bP^2$ .............(1)

where, B = aP = birth rate

D = $bP^2$ = death rate

Now initial population at t = 0, we have

$P_0$ = 220 , $B_0$ = 9 , $D_0$ = 15

Now equation (1) can be written as :

$\frac{dP}{dt}=P(a-bP)$

$\frac{dP}{dt}=bP(\frac{a}{b}-P)$ .................(2)

Now this equation is similar to the logistic differential equation which is ,

$\frac{dP}{dt}=kP(M-P)$

where M = limiting population / carrying capacity

This gives us M = a/b

Now we can find the value of a and b at t=0 and substitute for M

$a_0=\frac{B_0}{P_0}$ and $b_0=\frac{D_0}{P_0^2}$

So, $M=\frac{B_0P_0}{D_0}$

= $\frac{9 \times 220}{15}$

= 132

Now from equation (2), we get the constants

k = b = $\frac{D_0}{P_0^2} = \frac{15}{220^2}$

= $\frac{3}{9680}$

The population P(t) from logistic equation is calculated by :

$P(t)= \frac{MP_0}{P_0+(M-P_0)e^{-kMt}}$

$P(t)= \frac{132 \times 220}{220+(132-220)e^{-\frac{3}{9680} \times132t}}$

$P(t)= \frac{29040}{220-88e^{-\frac{396}{9680} t}}$

As per question, P(t) = 110% of M

$\frac{110}{100} \times 132= \frac{29040}{220-88e^{\frac{-396}{9680} t}}$

$220-88e^{\frac{-99}{2420} t}=200$

$e^{\frac{-99}{2420} t}=\frac{5}{22}$

Now taking natural logs on both the sides we get

t = 36.216

Number of months = 36.216

8 0

3 years ago