I don't know what the "six-step method" is supposed to be, so I'll just demonstrate the typical method for this problem.
Let <em>x</em> be the amount (in gal) of the 50% antifreeze solution that is required. The new solution will then have a total volume of (<em>x</em> + 60) gal.
Each gal of the 50% solution used contributes 0.5 gal of antifreeze. Similarly, each gal of the 30% solution contributes 0.3 gal of antifreeze. So the new solution will contain (0.5 <em>x</em> + 0.3 * 60) gal = (0.5 <em>x</em> + 18) gal of antifreeze.
We want the concentration of antifreeze to be 40% in the new solution, so we need to have
(0.5 <em>x</em> + 18) / (<em>x</em> + 60) = 0.4
Solve for <em>x</em> :
0.5 <em>x</em> + 18 = 0.4 (<em>x</em> + 60)
0.5 <em>x</em> + 18 = 0.4 <em>x</em> + 24
0.5 <em>x</em> - 0.4 <em>x</em> = 24 - 18
0.1 <em>x</em> = 6
<em>x</em> = 6/0.1 = 60 gal
The ratio of the geometric sequence 40
is 2.
Given that geometric sequence is 40* and we have to find the common ratio of all the terms.
Geometric sequence is a sequence in which all the terms have a common ratio.
Nth termof a GP is a
in which a is first term and r is common ratio.
Geometric sequence=40*
We have to first find the first term, second term and third term of a geometric progression.
First term=40*
=40*
=40*1
=40
Second term=40*
=40*
=40*2
=80
Third term=40*
=40*
=40*4
=160
Ratio of first two terms=80/40=2
Ratio of next two terms=160/80=2
Hence the common ratio of geometric sequence is 2.
Learn more about geometric progression at brainly.com/question/12006112
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Answer:
42.5m/s
Step-by-step explanation:
Divide by 40
1q+2=-6q+3+8q+4
1q+2=2q+7
<span>-2q -2q
</span>-q+2=7
<span> -2 -2
</span>-q=<span>5
-1 -1
q=-5
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