18 + 9x = 49
with the use of an equation you can easily find out if 6 weeks of saving up is enough to get the rabbit.
18 + 9(6) 
49
9 x 6 = 54
54 + 18 = 72
you could have enough money in 4 weeks
The number of tests that it would take for the probability of committing at least one type I error to be at least 0.7 is 118 .
In the question ,
it is given that ,
the probability of committing at least , type I error is = 0.7
we have to find the number of tests ,
let the number of test be n ,
the above mentioned situation can be written as
1 - P(no type I error is committed) ≥ P(at least type I error is committed)
which is written as ,
1 - (1 - 0.01)ⁿ ≥ 0.7
-(0.99)ⁿ ≥ 0.7 - 1
(0.99)ⁿ ≤ 0.3
On further simplification ,
we get ,
n ≈ 118 .
Therefore , the number of tests are 118 .
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Answer:
sin25 = cos65
Step-by-step explanation:
23. it increased by 12 because the difference between -4 and 8 is 12
24. 25 because 40 minus 15 is 25
26. 5 because 156 minus 96 equals 60 and 60 divided by 12 equals 5
Y=1\2x.
hopes this helps you
