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2 years ago

If f (12) =4(12)-20 which function represents f(x)?

Mathematics

2 answers:

AnnZ [28]2 years ago

7 0

Answer:

The graph of f (x)=[x+2] after it is translated 4 units to the right

frez [133]2 years ago

4 0

Answer:F(x)=4x-20

Step-by-step explanation:

The X on both sides is 12.

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Which of the following exponential functions goes through the points (1, 20) and (2, 80)?

levacccp [35]

F(x) = 5(4)^x is the correct answer.

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guapka [62]

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It is angle k and angle l

Step-by-step explanation:

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3 years ago

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fgiga [73]

Answer:

A. 7 pounds

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Step-by-step explanation:

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3 years ago

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Solve this thing pls <img src="https://tex.z-dn.net/?f=3%5Cleft%28q-7%5Cright%29%3D27" id="TexFormula1" title="3\left(q-7\ri

evablogger [386]

Answer:

Solution of equation ( q ) = 16

Step-by-step explanation:

In this question we have given an equation that is 3 ( q - 7 ) = 27 and we have asked to solve this equation that means to find the value of  q .

Solution : -

$\quad \: \longmapsto \: 3(q - 7) = 27$

Step 1 : Solving parenthesis :

$\quad \: \longmapsto \:3q - 21 = 27$

Step 2 : Adding 21 on both sides :

$\quad \: \longmapsto \:3q - \cancel{ 21} + \cancel{21} = 27 + 21$

On further calculations we get :

$\quad \: \longmapsto \:3q = 48$

Step 3 : Dividing by 3 from both sides :

$\quad \: \longmapsto \: \frac{ \cancel{3}q}{ \cancel{3}} = \cancel {\frac{48}{3} }$

On further calculations we get :

$\quad \: \longmapsto \: \pink{\boxed{\frak{q = 16}}}$

Therefore, solution of equation ( q ) is 16 .

Verifying : -

Now we are very our answer by substituting value of q in the given equation . So ,

3 ( q - 7 ) = 27

3 ( 16 - 7 ) = 27

3 ( 9 ) = 27

27 = 27

L.H.S = R.H.S

Hence, Verified.

Therefore, our solution is correct .

<h2>#Keep Learning</h2>

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2 years ago

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What is the perimeter of this quadrilateral? (5,5) (2, 4) (4, 1) (6, 1)

lbvjy [14]

$~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_1}{5}~,~\stackrel{y_1}{5})\qquad B(\stackrel{x_2}{2}~,~\stackrel{y_2}{4}) ~\hfill AB=\sqrt{[ 2- 5]^2 + [ 4- 5]^2} \\\\\\ AB=\sqrt{(-3)^2+(-1)^2}\implies \boxed{AB=\sqrt{10}} \\\\[-0.35em] ~\dotfill\\\\ B(\stackrel{x_1}{2}~,~\stackrel{y_1}{4})\qquad C(\stackrel{x_2}{4}~,~\stackrel{y_2}{1}) ~\hfill BC=\sqrt{[ 4- 2]^2 + [ 1- 4]^2}$

$BC=\sqrt{2^2+(-3)^2}\implies \boxed{BC=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ C(\stackrel{x_1}{4}~,~\stackrel{y_1}{1})\qquad D(\stackrel{x_2}{6}~,~\stackrel{y_2}{1}) ~\hfill CD=\sqrt{[ 6- 4]^2 + [ 1- 1]^2} \\\\\\ CD=\sqrt{2^2+0^2}\implies \boxed{CD=2} \\\\[-0.35em] ~\dotfill\\\\ D(\stackrel{x_1}{6}~,~\stackrel{y_1}{1})\qquad A(\stackrel{x_2}{5}~,~\stackrel{y_2}{5}) ~\hfill DA=\sqrt{[ 5- 6]^2 + [ 5- 1]^2}$

$DA=\sqrt{(-1)^2+4^2}\implies \boxed{DA=\sqrt{17}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{\Large Perimeter}}{\sqrt{10}~~ + ~~\sqrt{13}~~ + ~~2~~ + ~~\sqrt{17}}~~ \approx ~~ 12.89$

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