a+b+c=0
[(a+b+c)^2=a^2+b^2+c^2+2ab+2ac+2bc]
[a^2+b^2+c^2+2ab+2ac+2bc=0]
[a^2+b^2+c^2=-(2ab+2ac+2bc)]
[a^2+b^2+c^2=-2(ab+ac+bc)] (i)
also
[a=-b-c]
[a^2=-ab-ac] (ii)
[-c=a+b]
[-bc=ab+b^2] (iii)
adding (ii) and (iii) ,we have
[a^2-bc=b^2-ac] (iv)
devide (i) by (iv)
[(a^2+b^2+c^2)/(a^2-bc)=(-2(ab+bc+ca))/(b^2-ac)]
A is the correct answer.......
Here is the work shown:
x^2-x-20
A is the correct answer because when using the distributive property it is the only example that results in x^2-x-20.
(x+4)(x-5)
x*x=x^2, x*-5=-5x, 4*x=4x, 4*-5=-20. Now combine all alike terms for your final answer. x^2-x-20..
please vote my answer brainliest. thanks!
3 can be multiplied to 5 and the answer would be 15
3 can be added to 5 and the answer would be 8
Answer:
Step-by-step explanation:
We can use some logarithmic rules to solve this easily.
<em>Note: Ln means 
</em>
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Now, lets start with the equation:
Writing left side with logarithmic base e, we have:
We can now use the property shown below to make this into exponential form:
So, we write:
We recognize another property of exponentials:
So, we write:
Also, another property of natural logarithms is:
Now, we simplify:
This is the answer.
Answer: That would be 1 case + 112 pack + 16 pack + 5 singles
Step-by-step explanation:
