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polet [3.4K]
3 years ago
8

What is a counterexample to this claim ?

Mathematics
1 answer:
MaRussiya [10]3 years ago
6 0
Rectangle is the answer
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Find the average number particles hitting the surface perunit area and per unit time
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The length of a rectangular plot of land is 10 yards more than its width. If the area of the land 600 square yards , find the di
vagabundo [1.1K]
<span>Let the width of the rectangular plot of land be 'x' yards. Given that the length of the rectangular plot of land is 10 yards more than its width. So, width of the rectangular plot of land = (x + 10) yards. Also given that the area of the rectangular plot of land is 600 square yards. We know that, area of a rectangle = length * width That is, (x+10) * x = 600 x^2 + 10x = 600 x^2 + 10x - 600 = 0 x^2 + 30x - 20x -600 = 0 x(x + 30) - 20(x + 30) = 0 (x +30)(x -20) =0 Therefore, either (x + 30) = 0 or (x - 20) = 0 If x + 30 = 0, then x = -30 and If x - 20 = 0, then x = 20 Since 'x' represents the width of a rectangular plot of land it cannot be negative. Therefore, width of the rectangular plot of land = 20 yards length of the rectangular plot of land= x + 10 = 30 yards</span>
5 0
3 years ago
-7x-6y=-1
Xelga [282]
Cancel something
we cancel x's

multiply 1st equation by 5 and 2nd by 7 and add them
-35x-30y=-5
<u>35x-28y=7 +</u>
0x-58y=2

-58y=2
divide both sides by -58
y=-1/29
sub back
5x-4(-1/29)=1
5x+4/29=1
minus 4/29 from both sides
note, 1=29/29
5x=25/29
divide bot sides by 5 (or times 1/5)
x=5/29


(5/29,-1/29)
6 0
2 years ago
Previous
PilotLPTM [1.2K]

just realized this is an old question

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3 years ago
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