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3 years ago

Math help!?

Mathematics

1 answer:

laiz [17]3 years ago

6 0

Basically use pythagorean theorem to solve :))

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Determine whether each statement is always sometimes or never true explain your reasoning

Aneli [31]

17) Sometimes true

Given only that a quadrilateral is a parallelogram, we can only conclude the opposite sides are congruent - not the adjacent sides

18) Always true

Adjacent angles of a parallelogram are supplementary.

19) Always true.

Opposite sides of a parallelogram are congruent.

20) Never true

Diagonals of a parallelogram bisect each other, meankng that MR = RP.

8 0

2 years ago

Please help me with the below question.

Snezhnost [94]

6a. By the convolution theorem,

$L\{t^3\star e^{5t}\} = L\{t^3\} \times L\{e^{5t}\} = \dfrac6{s^4} \times \dfrac1{s-5} = \boxed{\dfrac5{s^4(s-5)}}$

6b. Similarly,

$L\{e^{3t}\star \cos(t)\} = L\{e^{3t}\} \times L\{\cos(t)\} = \dfrac1{s-3} \times \dfrac s{1+s^2} = \boxed{\dfrac s{(s-3)(s^2+1)}}$

7. Take the Laplace transform of both sides, noting that the integral is the convolution of $e^t$ and $f(t)$ .

$\displaystyle f(t) = 3 - 4 \int_0^t e^\tau f(t - \tau) \, d\tau$

$\implies \displaystyle F(s) = \dfrac3s - 4 F(s) G(s)$

where $g(t) = e^t$ . Then $G(s) = \frac1{s-1}$ , and

$F(s) = \dfrac3s - \dfrac4{s-1} F(s) \implies F(s) = \dfrac{\frac3s}{\frac{s+3}{s-1}} = 3\dfrac{s-1}{s(s+3)}$

We have the partial fraction decomposition,

$\dfrac{s-1}{s(s+3)} = \dfrac13 \left(-\dfrac1s + \dfrac4{s+3}\right)$

Then we can easily compute the inverse transform to solve for f(t) :

$F(s) = -\dfrac1s + \dfrac4{s+3}$

$\implies \boxed{f(t) = -1 + 4e^{-3t}}$

6 0

2 years ago

I need with this question please. Please help me

klemol [59]

Answer:

idk

Step-by-step explanation:

to lazy

7 0

3 years ago

What's the answer to tripling the greater of the two consecutive even integers gives the same result as subtracting 10 from the

Ostrovityanka [42]

let the 2 integers be x and x + 2.

so we have the equation:-

3(x + 2) = x - 10

3x + 6 = x - 10

2x = -16

x = -8

the integers are -8 and -6 answer

5 0

3 years ago

Nora measured the angles of a triangle. Two of the angles measured 20° What was the measure of the third angle of Nora’s triangl

aivan3 [116]

Answer:

140°

Step-by-step explanation:

The sum of angle of a triangle is equal to 180°.

Two of the angles measured 20°.

We need to find the measure of the third angle of Nora’s triangle. let the third angle is x. So,

20+20+x = 180

40+x = 180

x = 180-40

x = 140°

So, the third angle of the triangle is 140°.

8 0

3 years ago