300=2×2×5×5×3
We observe that 2 and 5 are grouped in pairs and the 3 is left unpaired.
If we multiply 300 by the factor 3 then
300×3=2×2×5×5×3×3
900=2×2×5×5×3×3 which is a perfect square.
∴ Required number is 3
root of 900 =30
Answer:
14units
Step-by-step explanation:
Let the vertices of a rectangle be A(3, 1), B(3, 5), C(6, 5), and D(6, 1).
Using the formula for calculating distance between two points;
AB =√(5-1)²+(3-3)²
AB = √4²
AB = 4
BC = √(5-5)²+(6-3)²
BC = √3²
BC =>3
CD = √(1-5)²+(6-6)²
CD = √(-4)²
CD = √16
CD = 4
AD= √(1-1)²+(6-3)²
AD = √3²
AD = √9
AD =3
Perimeter of the rectangle = AB+BC+BD+AD
Perimeter of the rectangle = 4+3+4+3
Perimeter of the rectangle = 14units
Answer:
so you can simplify the ratio
Step-by-step explanation:
Yes
Step-by-step explanation:
its a direct-variation function
(k - 1)(k - 4)
Use FOIL to solve this.
First
k * k
Outer
k * -4
Inner
-1 * k
Last
-1 * -4
k^2 - 4k - 1k + 4
k^2 - 5k + 4 is the trinomial.
