Question

Starting at home, Luis traveled uphill to the gift store for 50 minutes at just 6 mph. He then traveled back home along the same path down hill at a speed of 12 mph. What is his average speed for the entire trip from home to the gift store and back?

Answer 1

Answer:

Therefore his average speed for the entire trip is 8 mph.

Step-by-step explanation:

Given, In 50 minutes Luis traveled uphill to gift store at 6 mph.

6 mph  means in 1 h= 60 minutes Luis can covered 6 mile.

In 1 minutes Luis can covered $\frac{6}{60}$ mile.

In 50 minutes Luis can covered $\frac{6\times 50}{60}$  mile

                                                  = 5 mile

Again when he come back at home, the speed was 12 mph.

12 mph  means in 1 h= 60 minutes Luis can covered 12 mile.

Therefore he traveled 12 mile in 60 minutes

He traveled 1 mile in $\frac{60}{12}$  minutes.

He traveled 5 mile in $\frac{60\times 5}{12}$ minutes

                                   = 25 minutes.

Total distance for the entire trip is =(5+5) mile=10 mile

Total time for the entire trip is = (50+25) minutes = 75 minutes

$\textrm{Average speed}=\frac{\textrm{Total distance}}{\Textrm {total time}}$

                       $=\frac{10}{75}$ m/min

                      $=\frac{10\times 60}{75}$ mph

                      = 8 mph

Therefore his average speed for the entire trip is 8 mph.