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emmasim [6.3K]
4 years ago
11

Please it's urgent ans please​

Mathematics
1 answer:
svetoff [14.1K]4 years ago
6 0
The graph seems to not be the best quality but it looks closest to Y=(-3/5)x
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What is 240 more than 100
alexdok [17]

Answer:

340

Step-by-step explanation:

240 + 100 = 340

7 0
3 years ago
Read 2 more answers
Translate the phrase into an expression: 11 more than one third of a number
skelet666 [1.2K]
1/3x+11.
1/3 of a number can be shown as 1/3x, since the number is not identified.

We can represent 11 more as +11.
This, our expression is 1/3x+11

Hope this helps!
5 0
3 years ago
Anyone know how to dothis ??
Mars2501 [29]

Answer:

70 degrees.

Step-by-step explanation:

Add up all the values and divide by 5.

350/5 = 70.

5 0
3 years ago
Identify the vertex, axis of symmetry, minimum or maximum, domain, and range of the function f(
alekssr [168]

Identify the vertex, axis of symmetry, minimum or maximum, domain, and range of the function ()=−(+)^−

<em><u>Answer:</u></em>

vertex = (-4, -5)

Axis of symmetry = -4

use the (-4, -5) to find the minimum value

Domain = ( - \infty, \infty ) , [ x | x\ is\ real ]\\\\Range = [ -5, \infty ), y\geq -5

<em><u>Solution:</u></em>

Given function is:

f(x) = (x+4)^2 - 5

The equation in vertex form is given as:

y = a(x-h)^2+k

Where, (h, k) is constant

On comparing give function with vertex form,

h = -4

k = -5

Vertex is (-4 , -5)

Axis of symmetry : x co-ordinate of vertex

Thus, axis of symmetry = -4

The coefficient of x^2 is positive in given function.

Thus the vertex point will be a minimum

Minimum\ value = f(\frac{-b}{a})

f(x) = x^2 + 8x + 16 - 5\\\\f(x) = x^2 + 8x + 11

f(x) = ax^2+bx+c

On comparing,

a = 1

b = 8

x = \frac{-b}{2a} = \frac{-8}{2 \times 1} = -4

f(-4) = (-4)^2 + 8(-4) + 11 = 16 - 32 + 11 = -5

Thus, use the (-4, -5) to find the minimum value

Domain and range

f(x) = (x+4)^2 - 5

The domain is the input values shown on the x-axis

The range is the set of possible output values f(x)

Therefore,

Domain = ( - \infty, \infty ) , [ x | x\ is\ real ]\\\\Range = [ -5, \infty ), y\geq -5

4 0
3 years ago
At midnight, the outside temperature was -12.3 degrees. By 6:00 AM the outside tempature had dropped 6.8 degrees.
choli [55]
It was -19.1 degrees
7 0
3 years ago
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