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Yuki888 [10]
3 years ago
13

Translate the phrase into an expression: 11 more than one third of a number

Mathematics
1 answer:
skelet666 [1.2K]3 years ago
5 0
1/3x+11.
1/3 of a number can be shown as 1/3x, since the number is not identified.

We can represent 11 more as +11.
This, our expression is 1/3x+11

Hope this helps!
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Select the graph that represents the inequality <br><br> 2x + 3y &lt;= 6
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I think the answer is B, the one with a complete line and shaded to the bottom
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You and your friends have decided to camp for a night. Your friend claims the perimeter of his tent is 7.5 metres.
Georgia [21]
Perimeter =8.2
the friend is incorrect
4 0
3 years ago
4(10b-4) <br><br> Explain please
Angelina_Jolie [31]
<h3>Answer:   40b - 16</h3>

Work Shown:

4(10b-4)

4*10b - 4*4

40b - 16

I multiplied the outer term 4 by each term inside. Refer to the distribution property (aka distributive property).

4 0
2 years ago
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For the graphed exponential equation, calculate the average rate of change from x = −3 to x = 0.
iragen [17]

Answer:

-\frac{7}{3}

Step-by-step explanation:

To solve this, we are using the average rate of change formula:

m=\frac{f(b)-f(a)}{b-a}

where

m is the average rate of change

a is the first point

b is the second point

f(a) is the function evaluated at the first point

f(b) is the function evaluated at the second point

We want to know the average rate of change of the function f(x)=0.5^x-6 form x = -3 to x = 0, so our first point is -3 and our second point is 0. In other words, a=-3 and b=0.

Replacing values

m=\frac{f(b)-f(a)}{b-a}

m=\frac{0.5^0-6-(0.5^{-3}-6)}{0-(-3)}

m=\frac{1-6-(8-6)}{3}

m=\frac{-5-(2)}{3}

m=\frac{-5-2}{3}

m=\frac{-7}{3}

m=-\frac{7}{3}

We can conclude that the average rate of change of the exponential equation form x = -3 to x = 0 is -\frac{7}{3}

4 0
3 years ago
5. h(x)=0.5x - 1 with domain (-♾, 4) what is the range
Rudiy27

We have a domain of a function, that is, which x-es can we throw in. But we are asking which y-s will we get given that we can only throw x-es in (-\infty,4).

Let's try x=4 even though we are forbidden to put 4 inside h we are still able to do so.

So h(4)=0.5\cdot4-1=2-1=1 what we just got is the upper limit of the range. The lower limit is h(-\infty)=-\infty.

So the range is just (-\infty, 1).

Hope this helps :)

6 0
3 years ago
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