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2 years ago

Help plz asap i reward brainliest im being timed!!!!

Mathematics

2 answers:

Bumek [7]2 years ago

8 0

I looked it up on desmos, I am positive that this is the correct answer

Lera25 [3.4K]2 years ago

3 0

It should be 4 I think

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What is the absolute value of -5/8?

Gemiola [76]

well, -5/8 is -0.625.

the absolute value of -0.625 is 0.625.

and abs value of -5/8 is 5/8

7 0

3 years ago

Read 2 more answers

For the right triangle shown, which expression represents the length of CA?

Nataly [62]

Answer:

b. 5tan(25°)

Step-by-step explanation:

The tangent function gives the ratio between the side opposite and the side adjacent to the angle. That is ...

tan(25°) = ?/5

Multiplying by 5 solves the equation:

? = 5·tan(25°)

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3 years ago

Write g-12 in words

larisa [96]

I'm guessing you are looking for an algebraic sentence. In that case, 12 less than g would make sense, or 12 subtracted from g

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3 years ago

Determine the measure of each segment then indicate whether the statements are true or false

kupik [55]

Answer:

$d_{AB}\ne d_{JK}$

$d_{AB}\ne \:d_{GH}$

$d_{GH}\ne \:d_{JK}$

Therefore,

Option (A) is false

Option (B) is false

Option (C) is false

Step-by-step explanation:

Considering the graph

Given the vertices of the segment AB

A(-4, 4)

B(2, 5)

Finding the length of AB using the formula

$d_{AB}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

$=\sqrt{\left(2-\left(-4\right)\right)^2+\left(5-4\right)^2}$

$=\sqrt{\left(2+4\right)^2+\left(5-4\right)^2}$

$=\sqrt{6^2+1}$

$=\sqrt{36+1}$

$=\sqrt{37}$

$d_{AB}\:=\sqrt{37}$

$d_{AB}=6.08$ units

Given the vertices of the segment JK

J(2, 2)

K(7, 2)

From the graph, it is clear that the length of JK = 5 units

$d_{JK}=5$ units

Given the vertices of the segment GH

G(-5, -2)

H(-2, -2)

Finding the length of GH using the formula

$d_{GH}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

$=\sqrt{\left(-2-\left(-5\right)\right)^2+\left(-2-\left(-2\right)\right)^2}$

$=\sqrt{\left(5-2\right)^2+\left(2-2\right)^2}$

$=\sqrt{3^2+0}$

$=\sqrt{3^2}$

$\mathrm{Apply\:radical\:rule\:}\sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\ge 0$

$d_{GH}\:=\:3$ units

Thus, from the calculations, it is clear that:

$d_{AB}=6.08$

$d_{JK}=5$

$d_{GH}\:=\:3$

Thus,

$d_{AB}\ne d_{JK}$

$d_{AB}\ne \:d_{GH}$

$d_{GH}\ne \:d_{JK}$

Therefore,

Option (A) is false

Option (B) is false

Option (C) is false

8 0

3 years ago

Is sqrt(1 - sin^2 θ) = cos θ true? if so, in which quadrants does angle θ terminate?

jonny [76]

Answer:

I and IV

Step-by-step explanation:

Since 1-sin(θ)² = cos(θ)², the given equation is equivalent to ...

√(cos(θ)²) = |cos(θ)| = cos(θ)

This will be true where the cosine is non-negative, in the first and fourth quadrants.

7 0

3 years ago