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ahrayia [7]
3 years ago
8

Before inserting a preformatted table of contents, what must you do first?

Computers and Technology
1 answer:
vova2212 [387]3 years ago
6 0

Answer: apply heading styles to text.

Explanation:

You might be interested in
What is the biggest type of gear?<br><br>A. Spur<br>B.Worm<br>C.Wheel<br>D.Pinion
AnnZ [28]
The answer to this should be B. Worm. A pinion is a the smallest gear out of the listed ones above. spur would be next then wheel and the biggest if them all would be the spur. I'm not completely sure if my answer is 100% correct, but I feel confident enough about it. Hope this helps. :)

7 0
3 years ago
Read 2 more answers
Determine and prove whether an argument in English is valid or invalid. About Prove whether each argument is valid or invalid. F
yawa3891 [41]

Answer:

Each understudy on the respect roll got an A.  

No understudy who got a confinement got an A.  

No understudy who got a confinement is on the respect roll.  

No understudy who got an A missed class.  

No understudy who got a confinement got an A.  

No understudy who got a confinement missed class  

Explanation:

M(x): x missed class  

An (x): x got an A.  

D(x): x got a confinement.  

¬∃x (A(x) ∧ M(x))  

¬∃x (D(x) ∧ A(x))  

∴ ¬∃x (D(x) ∧ M(x))  

The conflict isn't considerable. Consider a class that includes a lone understudy named Frank. If M(Frank) = D(Frank) = T and A(Frank) = F, by then the hypotheses are overall evident and the end is counterfeit. Toward the day's end, Frank got a control, missed class, and didn't get an A.  

Each understudy who missed class got a confinement.  

Penelope is an understudy in the class.  

Penelope got a confinement.  

Penelope missed class.  

M(x): x missed class  

S(x): x is an understudy in the class.  

D(x): x got a confinement.  

Each understudy who missed class got a confinement.  

Penelope is an understudy in the class.  

Penelope didn't miss class.  

Penelope didn't get imprisonment.  

M(x): x missed class  

S(x): x is an understudy in the class.  

D(x): x got imprisonment.  

Each understudy who missed class or got imprisonment didn't get an A.  

Penelope is an understudy in the class.  

Penelope got an A.  

Penelope didn't get repression.  

M(x): x missed class  

S(x): x is an understudy in the class.  

D(x): x got a repression.  

An (ax): x got an A.  

H(x): x is on the regard roll  

An (x): x got an A.  

D(x): x got a repression.  

∀x (H(x) → A(x)) a  

¬∃x (D(x) ∧ A(x))  

∴ ¬∃x (D(x) ∧ H(x))  

Real.  

1. ∀x (H(x) → A(x)) Hypothesis  

2. c is a self-self-assured element Element definition  

3. H(c) → A(c) Universal dispatch, 1, 2  

4. ¬∃x (D(x) ∧ A(x)) Hypothesis  

5. ∀x ¬(D(x) ∧ A(x)) De Morgan's law, 4  

6. ¬(D(c) ∧ A(c)) Universal dispatch, 2, 5  

7. ¬D(c) ∨ ¬A(c) De Morgan's law, 6  

8. ¬A(c) ∨ ¬D(c) Commutative law, 7  

9. ¬H(c) ∨ A(c) Conditional character, 3  

10. A(c) ∨ ¬H(c) Commutative law, 9  

11. ¬D(c) ∨ ¬H(c) Resolution, 8, 10  

12. ¬(D(c) ∧ H(c)) De Morgan's law, 11  

13. ∀x ¬(D(x) ∧ H(x)) Universal hypothesis, 2, 12  

14. ¬∃x (D(x) ∧ H(x)) De Morgan's law, 13  

4 0
3 years ago
Given the code as follows: main() { int i = 3, n; float x; x = i; n = 8 % x; } What problem will occur? Group of answer choices
Bess [88]

Answer:

A compilation error will occur.

Explanation:

The % operator does not accept a float as its right-hand operand.

7 0
3 years ago
Write a program that will read in a line of text and output the number of words in the line and the number of occurrences of eac
kherson [118]

Answer:

Here is the C++ program:

#include<iostream>  //to use input output functions

#include <algorithm>  //to use tolower() function

using namespace std;  //to identify objects like cin cout

int main() {  //start of main function

 string text;  // to hold text input

 cout<<"Enter a line of text: ";  // prompts user to enter a string

 getline(cin,text);  // reads the input string (text) from user

transform(text.begin(), text.end(), text.begin(), ::tolower);  //converts the text into lower case

 int letter[26] = {0}; //to hold the letters

 int i;  // used as a loop variable

 int words=0;  // to hold the count of words

 for(i = 0; i< text.size();i++){  // iterates through the text

 if(isalpha(text[i])&&(text[i+1]=='.'||text[i+1]==','||text[i+1]==' '))  //checks if the character at i-th index of text is a letter, and checks if i+1 index position of text is a period, comma or a space

 words++;  // adds 1 to the count of words

 if(isalpha(text[i]))  // if the character at the i-th index of text is a letter

 letter[text[i]-'a']++;  }  // counts the occurrences of each letter

 char j = text[text.size()-1];  // sets j to the last character of text

 if(j != '.' && j!= ' '&& j!=',' &&j!= '\0')  //if the last character is not a period or empty space  or comma or end of lone

 words++;  //add 1 to the count of words

 cout<<"Number of words: "<<words<<endl;  //display the number of words in the text

 for(i=0; i<26; i++)  {  //iterates 25 times

   if(letter[i]>0)  //if letter at index i is greater than 0

   cout<<(char)('a'+i)<<" : "<<letter[i]<<endl;  }} //displays each letters and its number of occurrences in the text

 

Explanation:

The program is explained in the attached document with an example.

7 0
4 years ago
Consider the use of 1000-bit frames on a 1-Mbps satellite channel with a 270-ms delay. What is the maximum link utilization for,
natka813 [3]
I feel as if it would be B.
5 0
3 years ago
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