If you’re saying 0=v-2/1, then the numerator must be zero.
So v-2=0 so v=2.
Given:
θ = 54°
Radius = 10 in
To find:
The arc length of PQ
Solution:
Arc length formula:
![$\text{Arc length}=2 \pi r\left(\frac{\theta}{360^\circ}\right)](https://tex.z-dn.net/?f=%24%5Ctext%7BArc%20length%7D%3D2%20%5Cpi%20r%5Cleft%28%5Cfrac%7B%5Ctheta%7D%7B360%5E%5Ccirc%7D%5Cright%29)
![$\text{Arc length}=2 \times 3.14 \times 10\left(\frac{54^\circ}{360^\circ}\right)](https://tex.z-dn.net/?f=%24%5Ctext%7BArc%20length%7D%3D2%20%5Ctimes%203.14%20%5Ctimes%2010%5Cleft%28%5Cfrac%7B54%5E%5Ccirc%7D%7B360%5E%5Ccirc%7D%5Cright%29)
= 9.42 in
The arc length of PQ is 9.42 inches.
You can just do it by having enough building blocks lol
Lets see the answer to this question the fraction of the entire load of dirt in each mound is b.1/2 this is how i got my answer you multiply 3*1/6=1/2 so the fraction of the entire load of dirt that was in each mound is 1/2