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grandymaker [24]
3 years ago
15

What is the arclength of PQ

Mathematics
1 answer:
balu736 [363]3 years ago
6 0

Given:

θ = 54°

Radius = 10 in

To find:

The arc length of PQ

Solution:

Arc length formula:

$\text{Arc length}=2 \pi r\left(\frac{\theta}{360^\circ}\right)

$\text{Arc length}=2 \times 3.14 \times 10\left(\frac{54^\circ}{360^\circ}\right)

                 = 9.42 in

The arc length of PQ is 9.42 inches.

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PLZ ANSWER ASAP
svetlana [45]
Factor the following:
4 p (4 p - 1) - 3 (4 p - 1)^2

Factor 4 p - 1 from 4 p (4 p - 1) - 3 (4 p - 1)^2:
(4 p - 1) (4 p - 3 (4 p - 1))

-3 (4 p - 1) = 3 - 12 p:
(4 p - 1) (4 p + 3 - 12 p)

Grouping like terms, 4 p - 12 p + 3 = 3 + (4 p - 12 p):
(4 p - 1) (3 + (4 p - 12 p))
4 p - 12 p = -8 p:

Answer:  (4 p - 1) (-8 p + 3)

___________________________________________________
Factor the following:
m (m + n) - 3 m (m + n)^2

Factor m + n out of m (m + n) - 3 m (m + n)^2, resulting in (m + n) (m - 3 m (m + n)^(2 - 1)):
(m + n) (m - 3 m (m + n)^(2 - 1))

2 - 1 = 1:
(m + n) (m - 3 m (m + n))

Factor m out of m - 3 m (m + n), resulting in m (1 - 3 (m + n)):
m (1 - 3 (m + n)) (m + n)

-3 (m + n) = -3 m - 3 n:
Answer:  m (m + n) (-3 m - 3 n + 1)

___________________________________________________________Answer : -(-6 + p^2) (-1 - 6 q + p^2 q)

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Factor the following:
6 u^2 (2 u - 5)^2 - 12 u^2 (2 u - 5) (u + 5)

Factor u^2 out of 6 u^2 (2 u - 5)^2 - 12 u^2 (2 u - 5) (u + 5), resulting in u^2 (6 (2 u - 5)^2 - 12 (2 u - 5) (u + 5)):
u^2 (6 (2 u - 5)^2 - 12 (2 u - 5) (u + 5))

(2 u - 5) (2 u - 5) = (2 u) (2 u) + (2 u) (-5) + (-5) (2 u) + (-5) (-5) = 4 u^2 - 10 u - 10 u + 25 = 4 u^2 - 20 u + 25:
u^2 (6 4 u^2 - 20 u + 25 - 12 (2 u - 5) (u + 5))

6 (4 u^2 - 20 u + 25) = 24 u^2 - 120 u + 150:
u^2 (24 u^2 - 120 u + 150 - 12 (2 u - 5) (u + 5))

(u + 5) (2 u - 5) = (u) (2 u) + (u) (-5) + (5) (2 u) + (5) (-5) = 2 u^2 - 5 u + 10 u - 25 = 2 u^2 + 5 u - 25:u^2 (150 - 120 u + 24 u^2 - 122 u^2 + 5 u - 25)

-12 (2 u^2 + 5 u - 25) = -24 u^2 - 60 u + 300:
u^2 (-24 u^2 - 60 u + 300 + 24 u^2 - 120 u + 150)

Grouping like terms, 24 u^2 - 24 u^2 - 60 u - 120 u + 150 + 300 = (-120 u - 60 u) + (24 u^2 - 24 u^2) + (150 + 300):
u^2 ((-120 u - 60 u) + (24 u^2 - 24 u^2) + (150 + 300))

-120 u - 60 u = -180 u:
u^2 (-180 u + (24 u^2 - 24 u^2) + (150 + 300))
150 + 300 = 450:
u^2 (-180 u + (24 u^2 - 24 u^2) + 450)

24 u^2 - 24 u^2 = 0:
u^2 (450 - 180 u)

Factor 90 out of 450 - 180 u:
Answer:  u^2×90 (5 - 2 u)

_________________________________________________________

5 0
3 years ago
Identify the center<br> (x + 9)^2+ y^2= 64
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Your Center is : (-9,0).
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3 years ago
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The answer is A) left 3, up 2
7 0
3 years ago
Is 5/8 more than 11/20
alexdok [17]
5/8 is more than 11/20

If we find the lower common multiple of the denominators which is 160 then we can multiply the top numerators by the opposite denominators

5x20=100
11x8=88

We now have
\frac{100}{160}  and  \frac{88}{160}

The one on the left is simplified to 5/8 and the right is simplified to 11/20

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3 years ago
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12n = 3-5n-1 or n =3-5n-1???

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