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ikadub [295]
3 years ago
8

PLS HELP ASAP I WILL GIVE BRAINERLIST

Mathematics
2 answers:
makvit [3.9K]3 years ago
7 0

Answer:

4

Step-by-step explanation:

if x = 32 and y = 2, then you just have to substitute the numbers in:

\frac{32}{4 * 2}

so,

\frac{32}{8}

then you simplify

\frac{4}{1}

so the answer is 4

PilotLPTM [1.2K]3 years ago
4 0

Answer:

2

Step-by-step explanation:

Replace the variables with the real numbers

32/4 2

Multiply

4 x 3 = 12

Divide

32 / 12 = 2⅔

2⅔ ≈ 2

Answer: 2

Edit: Instead, go with D.) 4

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Answer:

1. & 3.

Step-by-step explanation:

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7 0
3 years ago
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Choose the expressions that are perfect cubes
Ludmilka [50]

Answer: the second fifth and sixth one

Step-by-step explanation:

4 0
3 years ago
Can you answer these please many thanks
givi [52]

Given: (a) 2(x+3)=2x+6 and (b) 4(y-3)=4y-12.

To find: The expanded form of the given expressions.

(c) 4(m+n)=4m+4n       (using a(b+c)=ab+ac)

(d) 3(5-q)=15-3q           (using a(b-c)=ab-ac)

(e) 5(2c+1)=10c+5          (using a(b+c)=ab+ac)

(f) 3(2x-5)=6x-15          (using a(b-c)=ab-ac)

(g) 7(4b-1)=28b-7          (using a(b-c)=ab-ac)

(h) 3(2x+y-5)=3((2x+y)-5)

⇒3(2x+y-5)=3(2x+y)-15         (using a(b-c)=ab-ac)

⇒3(2x+y-5)=6x+3y-15            (using a(b+c)=ab+ac)

(i) 2(6a-4b+3)=2((6a-4b)+3)

⇒2(6a-4b+3)=2(6a-4b)+6         (using a(b+c)=ab+ac)

⇒2(6a-4b+3)=12a-8b+6            (using a(b-c)=ab-ac)

(j)6(m+n+p)=6((m+n)+p)

⇒ 6(m+n+p)=6(m+n)+6p           (using a(b+c)=ab+ac)

⇒ 6(m+n+p)=6m+6n+6p            (using a(b+c)=ab+ac)

(k) y(y+2)=y^2+2y          (using a(b+c)=ab+ac)

(l) g(g-3)=g^2-3g           (using a(b-c)=ab-ac)

(m) n(4-n)=4n-n^2        (using a(b-c)=ab-ac)

(n) a(b+c)=ab+ac           (using a(b+c)=ab+ac)

(o) s(3s-4)=3s^2-4s        (using a(b-c)=ab-ac)

(p) 2x(x+5)=2x^2+10x     (using a(b+c)=ab+ac)

(q) 4y(x-3)=4xy-12y      (using a(b-c)=ab-ac)

(r) 5a(2b-5)=10ab-25a     (using a(b-c)=ab-ac)

(s) 4a(3b+2c)=12ab+8ac    (using a(b+c)=ab+ac)

(t) 5p(4p-5q)=20p^2-25pq    (using a(b-c)=ab-ac)

6 0
3 years ago
X2 + 7x – 18<br> x2 – 15x + 54
77julia77 [94]
(X-2)(x+9)
(X-9)(x-6)
5 0
3 years ago
The mass of a basket with 25 chocolate bars is 1110g. The mass of the empty basket is 310 g. A. What is the mass of 1 chocolate
shusha [124]

Answer:

A. 32 g

B. 3670 g

Step-by-step explanation:

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Basket: 310 g

25 bars: 1110 g - 310 g = 800 g

1 bar: 800 g / 25 = 32 g

105 bars: 105 × 32 g = 3360 g

Basket + 105 bars: 310 g + 3360 g = 3670 g

Answer:

A. 32 g

B. 3670 g

5 0
2 years ago
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