Answer:
w = (cv +dy) / (cb - ad)
Step-by-step explanation:
Multiply through by c
aw + y = c(bw + v) / d Multiply by d
d(aw + y) = c(bw + v) Remove the brackets
daw + dy = cbw + cv Subtract dy from both sides.
daw +dy - dy = cbw + cv -dy
daw = cbw + cv - dy Subtract cbw from both sides
daw - cbw = cbw - cbw + cv - dy
daw - cbw = cv - dy Isolate W on the left.
w(da - cb) = cv - dy Divide by cb - ad on both sides.
w = (cv - dy) / (ad - bc) Answer
Answer: ∠B = 42° ∠A = 23° ∠F = 115°
Step-by-step explanation:
∠B≅∠C alternate interior angles 42°
∠CDF is supplementary to ∠CDE,
so m∠CDF = 23° and ∠FAB≅∠CDF so m∠FAB= 23°
<em>also ∠A ≅ CDE corresponding angles 157° ∠FAB is suplementary to ∠A </em>
<em>so 180 - 157 = 23 gives the m∠FAB</em>
The sum of the angles of a triangle is 180°, so m∠AFB = 180 -(23 +42)
180- 65 = 115 = m∠F
Answer:
q = 4
Fully simplifying this equation gives you answer (A) q = 4
Hope this helps!
S+9
More than suggests addition.
