Question

What are the y-intercept of the function f(x)=-2x^2-3x+20?

Answer 1

Answer:

$\sf A) \ (-4, \ 0) \ and \ \ [\dfrac{5}{2} , \ 0]$

Explanation:

Given function: f(x) = -2x² - 3x + 20

To find the x-intercepts of a function, f(x) = 0

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-2x² - 3x + 20 = f(x)

-2x² - 3x + 20 = 0

-2x² - 8x + 5x + 20 = 0

-2x(x + 4) + 5(x + 4) = 0

(-2x + 5) (x + 4) = 0

-2x + 5 = 0, x + 4 = 0

-2x = -5, x = -4

x = -5/-2,x = -4

x = 5/2, x= -4

Coordinates: (-4, 0), (5/2, 0)