What are the y-intercept of the function f(x)=-2x^2-3x+20?
1 answer:
Answer:
Explanation:
Given function: f(x) = -2x² - 3x + 20
To find the x-intercepts of a function, f(x) = 0
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-2x² - 3x + 20 = f(x)
-2x² - 3x + 20 = 0
-2x² - 8x + 5x + 20 = 0
-2x(x + 4) + 5(x + 4) = 0
(-2x + 5) (x + 4) = 0
-2x + 5 = 0, x + 4 = 0
-2x = -5, x = -4
x = -5/-2,x = -4
x = 5/2, x= -4
Coordinates: (-4, 0), (5/2, 0)
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Answer:
13) ⇒
15) ⇒
Step-by-step explanation:
Given expression:
13)
15)
Write the expressions in radical form.
Solution:
For an expression with exponents as fraction like
the numerator represents the power it is raised to and the denominator
represents the nth root of the expression.
For an expression with exponents as negative fraction like
We take the reciprocal of the term by rule for negative exponents.
So it is written as:
using the above properties we can write the given expressions in radical form.
13)
⇒ [Using rule of negative exponents]
⇒ [writing in radical form]
15)
⇒ [Since 2nd root is given as
in radical form]