Answer:
27/77
Step-by-step explanation:
I hope this is correct
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The answer will not be without a variable unless you know what a is. Without discovering the a variable (a), to complete the problem, 6a+48
Answer:
The 95% confidece estimate for how much a typical parent would spend on their child's birthday gift is between $37.47 and $46.53.
Step-by-step explanation:
The results were roughly normal, so we can find the normal confidence interval.
We have that to find our level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of .
So it is z with a pvalue of , so
Now, find M as such
In which is the standard deviation of the population and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 42 - 4.53 = $37.47.
The upper end of the interval is the sample mean added to M. So it is 42 + 4.53 = $46.53.
The 95% confidece estimate for how much a typical parent would spend on their child's birthday gift is between $37.47 and $46.53.
16.5 because it would 165 divided by 10, so if you were to round it’s 17 because you can’t really get half a person.