The following steps of solving for the roots of 2x² - 4x -3 = 0 were retrieved from another source
Step 1 2x² - 4x = 3
Step 2 2(x² - 2x) = 3
Step 3 2(x² - 2x + 1) = 3 + 1
Step 4 2(x - 1)² = 4
From this, we can see that on Step 3, Tran made a mistake of adding 1 to 3. As we can see, 2(x² - 2x + 1) = 2x² - 4x + 2. That means, instead of adding 1, it should have been 2.
Therefore, the step that Tran first made an error is Step 3<span>.</span>
Answer:
A) 3π/4
B) 9π/7
C) 11π/6
Step-by-step explanation:
In the picture attached, the points are shown
Point A is between π/2 radians (90°) and π radians (180°). The only possible option is 3π/4
Point B is between π radians (180°) and 3π/2 radians (270°). The only possible option is 9π/7
Point C is between 3π/2 radians (270°) and 2π radians (360°). The only possible option is 11π/6
Answer:
9x+6
Step-by-step explanation:
2(x-4)= 2x-8
7(x+2)= 7x+14
2x-8+7x+14
clt
9x6
Answer:
Step-by-step explanation:
Using the midpoint formula, the coordinates of 
are 
.
cot(<em>θ</em>) = cos(<em>θ</em>)/sin(<em>θ</em>)
So if both cot(<em>θ</em>) and cos(<em>θ</em>) are negative, that means sin(<em>θ</em>) must be positive.
Recall that
cot²(<em>θ</em>) + 1 = csc²(<em>θ</em>) = 1/sin²(<em>θ</em>)
so that
sin²(<em>θ</em>) = 1/(cot²(<em>θ</em>) + 1)
sin(<em>θ</em>) = 1 / √(cot²(<em>θ</em>) + 1)
Plug in cot(<em>θ</em>) = -2 and solve for sin(<em>θ</em>) :
sin(<em>θ</em>) = 1 / √((-2)² + 1)
sin(<em>θ</em>) = 1/√(5)
