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Natali [406]
3 years ago
10

How many 4-digit numbers divisible by 5, all of the digits of which are even, are there?

Mathematics
2 answers:
Slav-nsk [51]3 years ago
8 0

Answer:

2000

2200

2220

3100

Step-by-step explanation:

tigry1 [53]3 years ago
3 0

Answer:

There are 4

2200

2000

3100

2220

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You are setting up a zip line in your yard. You map out your yard in a coordinate plane. An equation of the line representing th
neonofarm [45]

Answer:

Distance is 6.7units to the nearest tenth.

Explanation:

To solve this problem, we the distance formula. And this is given as:

D = \frac{|a x + b y + c|}{\sqrt{a^2 + b^2}}

We were given the equation:

y = 2 x + 4

This can also be rewritten as:

y – 2 x – 4 = 0.

Therefore, a = -2, b = 1 and c = -4

Also, we were given the points:

(x, y) = (–4, 11)

Making use of the above formula for distance, we have:

D = \frac{|-2\times -4 + 1\times 11 + -4|}{\sqrt{-2^2 + -4^2}}

D = \frac{15}{\sqrt{5}}

D = 6.7units (to the nearest tenth)

8 0
3 years ago
What will be the coordinates of point M of the image after the rotation?
LenKa [72]
Answer: b
explain- i’m smart jk
8 0
3 years ago
15-<br><br><br> pls help!!!!<br><br><br><br> math<br><br> pls help answer other questions<br> too
ddd [48]

Answer:

A

Step-by-step explanation:

The projection of vector B on unit vector a is

(B•a)a

av(unit vector of v)= 1/√2(-1,1)

u•av= 1/√2 × (-5+7)= √2

(u•av)av= √2 × 1/√2(-1,1)= (-1,1)

3 0
3 years ago
The curves y = √x and y=(2-x) and the Cartesian axes form two distinct regions in the first quadrant. Find the volumes of rotati
makkiz [27]

Answer:

Step-by-step explanation:

If you graph there would be two different regions. The first one would be

y = \sqrt{x} \,\,\,\,, 0\leq x \leq 1 \\

And the second one would be

y = 2-x \,\,\,\,\,,  1 \leq x \leq 2.

If you rotate the first region around the "y" axis you get that

{\displaystyle A_1 = 2\pi \int\limits_{0}^{1} x\sqrt{x} dx = \frac{4\pi}{5} = 2.51 }

And if you rotate the second region around the "y" axis you get that

{\displaystyle A_2 = 2\pi \int\limits_{1}^{2} x(2-x) dx = \frac{4\pi}{3} = 4.188 }

And the sum would be  2.51+4.188 = 6.698

If you revolve just the outer curve you get

If you rotate the first  region around the x axis you get that

{\displaystyle A_1 =\pi \int\limits_{0}^{1} ( \sqrt{x})^2 dx = \frac{\pi}{2} = 1.5708 }

And if you rotate the second region around the x axis you get that

{\displaystyle A_2 = \pi \int\limits_{1}^{2} (2-x)^2 dx = \frac{\pi}{3} = 1.0472 }

And the sum would be 1.5708+1.0472 = 2.618

7 0
4 years ago
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