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yarga [219]
2 years ago
9

Estelle drew two parallel lines, PQ and RS, intersected by a transversal KL, as shown below: Two parallel lines, PQ and RS, are

drawn with KL as a transversal intersecting PQ at point M and RS at point N. Angle KMQ is shown congruent to angle MNS. Which fact would help Estelle prove the measure of angle KMQ is equal to the measure of angle MNS? When both angle KMQ and angle MNS are equal to angle RNM, the angles KMQ and MNS are congruent. When same-side, consecutive interior angles QMN and PMN are complementary, the angles KMQ and MNS are congruent. When alternate interior angles QMN and MNR are supplementary, angles KMQ and MNS are congruent. When both angles KMQ and MNS are equal to angle PMN, the angles KMQ and MNS are congruent.
Mathematics
2 answers:
Kryger [21]2 years ago
4 0

Answer:

I'm pretty sure the answer is d,(When both angle KMQ and MNS are equal to angle PMN, the angles KMQ and MNS are congruent.)

Step-by-step explanation:

I had this question on my practice exam for my midterm.

anzhelika [568]2 years ago
3 0

Answer:

i believe that the answer is the last  one, d

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Which values of k would cause this system of equations to have no solution? Check all that apply.
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Answer:

x= -2y/3

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Step-by-step explanation:

Answer In cases of two equations having two unknown variables the simultaneous method of solving the equations is adopted.

Supposing “0” as the value of “k” we will have the equation as 3x+2y=0

Then separating variable x will give, x= -2y/3

Substituting the value of x into the first equation that is: 6x + 4y = 14

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Thus, no solution.

5 0
3 years ago
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GIVING BRAINIEST IF CORRECT!!<br> Find the area of the shaded region.
Andreyy89
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Which statement is true?
gayaneshka [121]

Answer:

Option: C is the correct answer.

C. Buying a needle and buying thread are dependent events.

Step-by-step explanation:

let A denotes the events of buying a thread.

and B denote the event of buying a needle.

Then A∩B denote the event of buying a needle and  a thread.

Also let P denote the probability of an event.

i.e. we are given:

P(A)=0.15

Also P(B|A)=0.25

As we know that:

P(B|A)=\dfrac{P(A\bigcap B)}{P(A)}\\\\i.e.\\\\0.25=\dfrac{P(A\bigcap B)}{0.15}\\\\i.e.\\\\P(A\bigcap B)=0.0375

As we know that when two events A and B are independent then,

P(A∩B)=∅

otherwise they are dependent events.

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3 years ago
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there are five bells which ring at interval of 4,5,12 and 15 minutes respectively at what minute those bells ring at the same ti
Rus_ich [418]
<h3>Answer:   60 minutes</h3>

=====================================================

Explanation:

Let's find the LCM of 4 and 5, which are the first two items of the list.

  • multiples of 4 are: 4,8,12,16,20,24,...
  • multiples of 5 are: 5,10,15,20,25,...

The smallest item in each list is 20, so the LCM of 4 and 5 is 20.

We can replace the "4,5" in the list "4,5,12,15" with "20". So our new list would be "20,12,15".

We then repeat the process of finding the LCM of the first two items

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LCM of 20 and 12 is 60.

The list "20,12,15" condenses to "60,15".

Repeat this process of finding the LCM once more and you'll find the overall LCM is 60.

Therefore, the LCM of the entire set {4,5,12,15} is 60. This is the smallest multiple shared by all four values. Interestingly enough, the outer values pair up to multiply to 60, and so do the inner values.

4*15 = 60

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In other words, all of the bells ring together at the same time every hour (perhaps at the top of every hour; eg at 7:00 pm and at 8:00 pm, etc).

8 0
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