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3 years ago

What is the area of a pizza with a diameter of 12 inches?

Mathematics

1 answer:

OleMash [197]3 years ago

7 0

I don't know but i think 113.09733552923255

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Write the equation of the line that passes through 7, 0 and is parallel to y = -3x + 4

Mazyrski [523]

Answer:

y = - 3x + 21

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = - 3x + 4 ← is in slope- intercept form

with slope m = - 3

Parallel lines have equal slopes , then

y = - 3x + c ← is the partial equation

To find c substitute (7, 0 ) into the partial equation

0 = - 21 + c ⇒ c = 0 + 21 = 21

y = - 3x + 21 ← equation of parallel line

8 0

3 years ago

Solving a _____ is the process of calculating unknown side lengths or angle measures of a triangle if certain of the side length

Ray Of Light [21]

ANSWER

C) Triangle

EXPLANATION

Solving a triangle is the process of calculating unknown side lengths or angle measures of a triangle if certain of the side lengths and/or angle measures are known.

We use the sine rule and cosine rule to find the missing sides and angles.

If the triangle has a right angle, then this is a special case, where we can use the trigonometric ratios and the Pythagoras theorem to find the unknown angles and sides.

6 0

3 years ago

Read 2 more answers

Can't figure out how to set up and check to see if right. 8/11(n-10)=64

strojnjashka [21]

Answer:

Step-by-step explanation:

$\frac{8}{11}(n-10)=64\\\\\frac{8(x-10)}{11}=64\\ 8(x-10) = 64(11)\\8(x-10) = 704\\8x-80 = 704\\8x= 704+80\\8x=784\\\\\frac{8x}{8}=\frac{784}{8} \\x=98$

7 0

3 years ago

How to prove this???

swat32

$\cos^3 2A + 3 \cos 2A \\
\Rightarrow \cos 2A (\cos^2 2A + 3) \\
\Rightarrow (\cos^2 A - \sin^2 A) (\cos^2 2A + 3) \\
\Rightarrow (\cos^2 A - \sin^2 A) (1 - \sin^2 2A + 3) \\
\Rightarrow (\cos^2 A - \sin^2 A) (4 - \sin^2 2A) \\
\Rightarrow (\cos^2 A - \sin^2 A) (4 - (2\sin A \cos A)(2\sin A \cos A)) \\
\Rightarrow (\cos^2 A - \sin^2 A) (4 - 4\sin^2 A \cos^2 A) \\ 
\Rightarrow 4(\cos^2 A - \sin^2 A) (1 - \sin^2 A \cos^2 A) 
$

go to right side now

$4( \cos^6 A - \sin^6 A)\\
\Rightarrow 4( \cos^3 A - \sin^3 A)(\cos^3 A + \sin^3 A)$

use $x^3 - y^3 = (x-y)(x^2 + xy + y^2)$ and $x^3 + y^3 = x^2 - xy + y^2$

$4( \cos^6 A - \sin^6 A)\\ \Rightarrow 4( \cos^3 A - \sin^3 A)(\cos^3 A + \sin^3 A) \\
\Rightarrow 4(\cos A - \sin A)(\cos^2 A + \cos A \sin A + \sin^2 A) \\
~\quad \quad\cdot ( \cos A + \sin A)(\cos^2 A - \cos A \sin A + \cos^2 A)$

so $\sin^2 A + \cos^2 A = 1$

$4( \cos^6 A - \sin^6 A)\\ \Rightarrow 4(\cos A - \sin A)(\cos^2 A + \cos A \sin A + \sin^2 A) \\ ~\quad \quad\cdot ( \cos A + \sin A)(\cos^2 A - \cos A \sin A + \cos^2 A) \\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 + \cos A \sin A )(1- \cos A \sin A ) \\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 - \cos^2 A \sin^2 A )\\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 - \sin^2 A \cos^2 A ) \\
 \Rightarrow Left hand side$

4 0

3 years ago

Does (2,0) work as a solution to the systems of equations to lines 3x+y=6 and 3x-y=6

fenix001 [56]

Answer:

Yes

Step-by-step explanation:

To see if (2,0) works as a solution to the systems of equations, we plug in the values of x and y and simplify. If the results are equal, then (2,0) is a solution.

3x + y = 6:

$3(2) + 0 = 6$
$6 + 0 = 6$
$6 = 6$
(2,0) is a solution to this equation.

3x - y = 6:

$3(2) - 0 = 6$
$6 - 0 = 6$
$6 = 6$
(2,0) is a solution to this equation.

Therefore, the answer is yes, it does work as a solution.

Have a lovely rest of your day/night, and good luck with your assignments! ♡

7 0

2 years ago